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awk help - Simple question

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# 1  
Old 04-03-2013
awk help - Simple question
I have what a think is a simple question but I'm just a beginner in scripting. I'm my unix command line I run a date command that returns the following:

Code:
Wed Apr  3 10:39:30 EDT 2013

How do I awk out the "10" only in awk? Or is awk the way to do it or is there a better way?
Last edited by Scrutinizer; 04-03-2013 at 01:41 PM.. Reason: code tags
# 2  
Old 04-03-2013
You can simply run date with format control to get hour:
Code:
date +%H

This User Gave Thanks to Yoda For This Post:
scj2012
# 3  
Old 04-03-2013
Code:
echo 'Wed Apr  3 10:39:30 EDT 2013' | awk -F'[ :]' '{print $4}'
date +%H

This User Gave Thanks to vgersh99 For This Post:
scj2012
# 4  
Old 04-03-2013
Thanks. How can I get it to recognize the hour variable?

Code:
hour=date +%H -d "1 hour ago"

i=test.`date +%Y%m%d`-$hour3101.txt

Last edited by Scrutinizer; 04-03-2013 at 01:41 PM.. Reason: code tags
# 5  
Old 04-03-2013
Use command substitution $(..)
Code:
hour=$(date +%H -d "1 hour ago")

This User Gave Thanks to Yoda For This Post:
scj2012
# 6  
Old 04-03-2013
Code:
hour=$(date +%H -d "1 hour ago")

i=$(grep Multiple test.`date +%Y%m%d`-$hour3101.txt)

I'm still missing something. I'm getting the following error:

Code:
grep: test.20130403-.txt: No such file or directory..

So it's not picking up the hour variable.
Last edited by Scrutinizer; 04-03-2013 at 01:40 PM.. Reason: code tags
# 7  
Old 04-03-2013
Code:
i=$( grep Multiple "test.`date +%Y%m%d`-${hour}3101.txt" )

The curly brace form is unambiguous as the variable name is clearly delimited.
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scj2012
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