Shell Programming and Scripting

Hi,

I need to search a word in the java file.

Assume the line in the java file is, (the line was splitted into 3 lines)

1.operationContext.sendFeedback(2.FeedbackType.ERROR, null, "Input is empty.", "Input Details: pr
3.ovide Valid pair(s): "+pairType);

When i grep for the word "sendFeedback", it is giving the first line only.

The output is,
operationContext.sendFeedback(

But i need whole line till ";" i.e.

1.operationContext.sendFeedback( 2.FeedbackType.ERROR, null, "Input is empty.", "Input Details: pr
3.ovide Valid pair(s): "+pairType);

Please provide me a command to get the output as above.

Thanks and Regards,
Tulasi






I need the command

grep's output is correct based on the regular expression...dont expect it to output multilines unless there are multiple "-e" switches on the command line or use another tool to extract that info...

Code:

perl -0777 -ne '/[^\n]*sendFeedback.*?;/s && print "$&\n"' FILE

For multiple occurrences:

Code:

perl -0777 -ne 'print "$&\n\n" while /[^\n]*sendFeedback.*?;/gs' FILE

Thanks for your Replies Yazu and Shamrock.
Yazu/Shamrock,
Actually my intention is, when we use grep command it will print Filename, line number and the whole line having the word it matches.

Along with that i want the next few lines which ends with ";" also.

For Ex: Suppose if am search for "showAndLogWarning" in all the files. my script is printing as below,

Script is :

Code:

#!/usr/bin/ksh
files=`find ./ -name "*.java"`
fileNames=`echo ${files}`
grep -i -n "logWarning" ${fileNames} > logMessages.txt

and the output is,

Code:

./DLSLogger.java:144:   public abstract void showAndLogWarning(OperationContext opContext, String message);
 ./MOTCM01450919/PlanetNeighborData.java:214:                            logging.showAndLogWarning(oprContext, "The LTE
SRCCELL" + nbrCellDn

When you see the above output, in line 214 it is incomplete when compared to line 144.

Please suggest me a command.

Thanks and Regards,
Tulasi Ram.Bora

Moderator's Comments:

How to use code tags when posting data and code samples.

Code:

awk '/sendFeedback\(/,/\)/' infile

Thanks rdcwayx,

The command is working. But as i said, the result should contain Filename and line number also.

Thanks and Regards,
Tulasi Ram.Bora

Try:

Code:

awk '/sendFeedback/{print FILENAME":"NR": "$0}' RS=\; ORS=";\n" infile