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Hexadecimal increment using shell script

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# 1  
Old 01-10-2012
Hexadecimal increment using shell script
I am looking for hexadecimal increment by reading user input using shell script. For example the user input is 01A. I want to increase the hex count by 4 times

Looking for output:

01A
O1B
01C
01D
01E

Can someone suggest?
# 2  
Old 01-10-2012
to start with:
Code:
echo 'obase=ibase=16;1A+1' |bc

These 2 Users Gave Thanks to vgersh99 For This Post:
fpmurphy rbatte1
# 3  
Old 01-10-2012
Hi sai_1712,

One way using perl:
Code:
$ perl -e '$var = 0x01A; for ( 1 .. 5 ) { printf qq[%03X\n], $var++ }'
01A
01B
01C
01D
01E

Regards,
Birei
# 4  
Old 01-11-2012
Thank you vgersh99 & birei for suggestion...

I am new to shell scripting. This hexadecimal increment count is part of my customized script. I get the output like below when i run my script

Cat lun.txt
01A
01A

The line1 & line2 values in lun.txt are same.The lun.txt output varies when ever I run my script and the increment count also varies it may be 2 or 3 or 4 depend upon requirement

I want to call the line1 variable(hexadecimal) from lun.txt file and increment by 2 or 3 or 4......... times which will define by user.

Your suggestions will be more helpful to complete my customized script.

Please note that I've written my script in shell
# 5  
Old 01-11-2012
Code:
#!/bin/ksh

incr=3
while read val
do
   echo "obase=ibase=16;${val}+${incr}" |bc
done < lun.txt

# 6  
Old 01-11-2012
Using bash:

Code:
#!/bin/bash
incr=4
while read val
do
  printf "%X\n" $((0x${val}+incr))
done < lun.txt

or perhaps your after:
Code:
read -p "Enter increment: " inc
read -p "Enter HEX value: " hex
printf "HEX + increment is: %X\n" $((0x$hex+inc))

Last edited by Chubler_XL; 01-11-2012 at 08:43 PM..
# 7  
Old 01-17-2012
Hello vgersh99,

When I use the below code I am getting the below output.
Code:
#!/bin/bash
incr=3
while read val
do
   echo "obase=ibase=16;${val}+${incr}" |bc
done < lun.txt

Output:
Code:
1D

***********************
lun.txt file contains
Code:
01A

***********************


I am looking for the below output. The increment is variable and to be defined by the user every time depend on requirement
Code:
01A
01B
01C
01D

---------- Post updated at 04:06 PM ---------- Previous update was at 04:00 PM ----------

Hello Chubler,

The below code is not working. Please let me know where I've to modify.The increment is a variable and to be defined by the user every time depend on requirement
Code:
#!/bin/bash
read -p "Enter increment: " inc
read -p "Enter HEX value: " hex
printf "HEX + increment is: %X\n" $((0x$hex+inc))

Code:
#!/bin/bash
incr=4
while read val
do
  printf "%X\n" $((0x${val}+incr))
done < lun.txt

Output:
Code:
syntax error at line 5: `(' unexpected


Code:
#!/bin/bash
read -p "Enter increment: " inc
read -p "Enter HEX value: " hex
printf "HEX + increment is: %X\n" $((0x$hex+inc))

Output:
Code:
-p: is not an identifier


Moderator's Comments:
Mod Comment How to use code tags
Last edited by Franklin52; 01-17-2012 at 06:54 AM.. Reason: Please use code tags for code and data samples, thank you
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