Shell Programming and Scripting

Hi there

I have a .ksh script that I am using on an AIX ( Actual Level 5.3.10.0, Maintenance Level 5.3.0.0) where I am logging into a windows box, doing a file count on that server and returning the output to the UNIX session.

I would like to exit the script at this point in time if the value is greater than 1. I have attempted to write this function into the script, but the variable that I am setting is not being echoed out as required.

When I run the script below, the result is

The value of $numfiles is returned, but not incorporated into the output.

Code:

#!/usr/bin/ksh

numfiles=$(ssh <SERVER> cmd /c 'dir/b/a-d <PATH> | find /c ".CSV"')

print $numfiles

if [ $numfiles -gt 0 ]
  then
     echo "There are "$numfiles" in the <PATH> directory. Transfer has been stopped."
fi

Can anyone assist with a solution to this issue?

Any help would be greatly appreciated

what is the output of print statement ?

Code:

 
print $numfiles

It prints out the correct value, in this case 1 (I have verified that there is only 1 file in the directory!)

In your statement, you mentioned "I would like to exit the script at this point in time if the value is greater than 1"

But you are checking for > 0 in condition

replace your if condition as below and let me know the output

Code:

 
if [ $numfiles -gt 0 ]
then
echo "$numfiles"
     echo "There are "$numfiles" in the <PATH> directory. Transfer has been stopped."
else
echo "$numfiles"
fi

Thanks for your help. I have replaced the if statement an re ranit. It has returned the following:

replace the echo statement. seems, your $numfiles is holding the value of 1

Code:

echo "There are $numfiles in the <PATH> directory. Transfer has been stopped."

I had tried that before itkamaral, but it returns the same results:

Would you have any other suggestions?