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Shell Programming and Scripting

Delete Photos Script

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# 1  
Old 04-14-2011
Delete Photos Script
Good Morning, I need to move a social networking site to another server and I need to delete a bunch of photos. The old site used to allow, our members, to upload up to 100 photos. Now I want to limit it to 10. How can I delete the remaining photos? Here is what it looks like: 2474-14637.jpg 2474-14638.jpg 2474-14639.jpg ... 2474-14650.jpg
# 2  
Old 04-14-2011
How do we know which photos belongs to which user?
# 3  
Old 04-14-2011
2474 is the UserID UserID-PhotoID.jpg
# 4  
Old 04-14-2011
See if this works for you:

Code:
#!/usr/bin/ksh
typeset -i mCnt
ls -1 | sort > File_List
IFS="-"
while read mUser mSuffix
do
  if [[ "${mUser}" != "${mPUser}" ]]; then
    mCnt=1
  fi
  if [[ ${mCnt} -gt 10 ]]; then
    mFName=${mUser}'-'${mSuffix}
    echo "Now deleting <${mFName}>"
    rm -f ${mFName}
  fi
  mPUser=${mUser}
  mCnt=${mCnt}+1
done < File_List

# 5  
Old 04-14-2011
That worked perfectly! Thank you. I never throught of a do if loop.
# 6  
Old 04-14-2011
confirm the command is right
Code:
ls *.jpg |awk -F - '++a[$1]>2' |xargs echo

do the clean:
Code:
ls *.jpg |awk -F - '++a[$1]>10' |xargs rm

# 7  
Old 04-15-2011
Quote:
Originally Posted by rdcwayx
confirm the command is right
Code:
ls *.jpg |awk -F - '++a[$1]>2' |xargs echo

do the clean:
Code:
ls *.jpg |awk -F - '++a[$1]>10' |xargs rm

ls *.jpg |awk -F - '++a[$1]>10' |xargs rm -bash: /bin/ls: Argument list too long rm: missing operand
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