I would like some help with a very basic script that I think should work but when from cron it doesn't. When ran manually it works fine. The script goes something like this
Code:
cd /wfmtransfer/import/agents/changed
for i in `ls -1 *.xml`
do
[something] --this will create a .OUT file
check=`grep Failure $i.OUT|wc -l`
if [ $check -ge 1 ]
then
mv $i.OUT /wfmtransfer/imports/agents/Failure
cp $i /wfmtransfer/imports/agent/Failure/originals
cp $i /wfmtransfer/imports/agents/original_file
else
mv $i.OUT /wfmtransfer/imports/agent/Success
cp $i /wfmtransfer/imports/agents/original_file
fi
done
When the script runs from cron I get a copy in the original_file folder but nowhere else and I can't figure this out at all. Running the script manually works fine.
Any help would be greatly appreciated.
Thanks,
G
---------- Post updated at 05:52 AM ---------- Previous update was at 05:39 AM ----------
Its ok I figured it out
Last edited by Franklin52; 01-20-2011 at 06:48 AM..
Reason: Please use code tags and indent your code
No need to use ls. Filename generation works always in command line, not only with ls.
You can use grep exit status, no need to count output lines
Code:
cd /wfmtransfer/import/agents/changed
for i in *.xml
do
[something] --this will create a .OUT file
if grep Failure $i.OUT >/dev/null 2>&1
then
mv $i.OUT /wfmtransfer/imports/agents/Failure
cp $i /wfmtransfer/imports/agents/Failure/originals
cp $i /wfmtransfer/imports/agents/original_file
else
mv $i.OUT /wfmtransfer/imports/agents/Success
cp $i /wfmtransfer/imports/agents/original_file
fi
done
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