Shell Programming and Scripting

I am sure there would be many ways to get this done other than awk, so feel free to give use any tool to fix this:

1. I ran 'ps -ef| grep SIU' and got this output:

I want to filter everything after the first '/' sign.

I tried this but didn't work the way it was required:

What command can be used to show everything starting from the first '/' sign?

Hi.

You want to keep everything after the first /?

Like:

Code:

$ ps ... | sed "s/[^/]*//"
/usr/bin/sh /opt/SIU/DSR/scripts/dsr_control_sms_file_processing.sh T 04 C 
/opt/SIU/bin/collector -JVMargs /var/opt/SIU/T_X_SMS_CL_SPLIT_C/JVMargs.ini -l 4 -n T_X_SMS_CL_SPLIT_C

The same in awk:

Code:

ps ... | awk 'sub(/[^\/]*/, "")'
/usr/bin/sh /opt/SIU/DSR/scripts/dsr_control_sms_file_processing.sh T 04 C 
/opt/SIU/bin/collector -JVMargs /var/opt/SIU/T_X_SMS_CL_SPLIT_C/JVMargs.ini -l 4 -n T_X_SMS_CL_SPLIT_C

Hi,
have You tried this?

Code:

ps -ef| grep SIU | cut -d/ -f2-

I know it drops the first slash but that can be fiddled with...

/Lakris

Worked perfectly! Just curious if you could tell the logic behind the syntax of awk command - doesn't get into my head (basically, will try to see the logic/syntax the way you look at that).

Thanks

---------- Post updated at 03:36 PM ---------- Previous update was at 03:33 PM ----------

---------- Post updated at 03:33 PM ---------- Previous update was at 03:22 PM ----------

worked just fine with little fiddling:
Amazing is the difference between -f2 and -f2-

I feel the inclination to learn scripting and related tools for that lol. Can anyone throw some light on what would be the most efficient path to learning scripting and related tools?

Thanks to the two gurus for their instant help!

An awk script, in it's simplest form would be a series of:

Code:

 pattern { actions }

An action would be performed if a pattern is true (be it a regular expression, a condition, or any combination of the two), and the default action if none is specified is { print }. That's to say an action would be performed if there is no condition specified.

As sub would always be true, while still performing the substitution, you can specify it as a "pattern" instead of just and action.

I.e

Code:

awk 'sub(/[^\/]*/, "")'

Is the same as:

Code:

awk '{ sub(/[^\/]*/, ""); print }'

The regular expression itself matches any character that isn't a / (from the start of the line - which is implicit in this case), and removes it, leaving only the slash and everything that follows.

With cut, the difference between -f2 and -f2- is not so amazing.

The first means field 2, while the second means field 2 onwards.

Code:

cut -f2      # field 2 only
cut -f2-10   # fields 2 to 10
cut -f2-     # field 2 up to whatever there is

The best resource is a search engine

Thank you... I use the search engine and when I am stuck, unix.com is a great place to discuss and get answers to unanswered questions

Can you advise of any web-link that could teach perl in 1 - 2 weeks - there are tons on the internet and I am not sure which one to pick!

Cheers

Here is a good start.
Tutorials - perldoc.perl.org

I suggest buying a book. As for learning it in 1-2 weeks -- good luck. FYI perl is the interpreter and Perl is the language.