09-09-2010
Awk question?
I am sure there would be many ways to get this done other than awk, so feel free to give use any tool to fix this:
1. I ran '
ps -ef| grep SIU' and got this output:
PHP Code:
dsradm 11254 1 0 Jun 10 ? 29:39 /usr/bin/sh /opt/SIU/DSR/scripts/dsr_control_sms_file_processing.sh T 04 C
dsradm 13067 16877 0 Jun 10 ? 2334:56 /opt/SIU/bin/collector -JVMargs /var/opt/SIU/T_X_SMS_CL_SPLIT_C/JVMargs.ini -l 4 -n T_X_SMS_CL_SPLIT_C
I want to filter everything after the first '/' sign.
I tried this but didn't work the way it was required:
PHP Code:
to5iumc2:/tmp ps -ef | grep SIU | awk -F/ '{print $NF}'
dsr_control_sms_file_processing.sh T 04 C
JVMargs.ini -l 4 -n T_X_SMS_CL_SPLIT_C
What command can be used to show everything starting from the first '/' sign?
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