substract column based on some criteria


 
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# 8  
Old 03-19-2010
Where is the -1? Anyway, there was a bug in the code (forgot to set a variable at the end: b=$3) but this should work:

Code:
$ cat file
-----
ABC      4675209        4676057          Pattern01
ABC      4676269        4676713          Pattern01
ABC      4682346        4682510          Pattern01
ABC      4682606        4682796          Pattern01
-----
ABC      48341587       48344548         Pattern09
-----
ABC      34297519       34298743         Pattern10
ABC      34298957       34299678         Pattern10
-----
$ awk '/-----/{
  if(f){
    print "Xyz\t0"  "\t" s
  }
  print; getline
  a=$2; b=$3; s=$NF; f=1		# a = column2(row1), b = row1(column3)
  next
}
/ABC/{
  if(a>$2){				# if column2(row1) > column2(row2)
    print "Xyz\t" a-$3 "\t" $NF	# + print row1(column2)-row2(column3)-1
  }
  else {
    print "Xyz\t" $2-b "\t" $NF	# else print row2(column2)-row1(column3)-1
  }
   
  a=$2; b=$3; f=0
}' file
-----
Xyz     212     Pattern01
Xyz     5633    Pattern01
Xyz     96      Pattern01
-----
Xyz     0       Pattern09
-----
Xyz     214     Pattern10
-----

# 9  
Old 03-19-2010
Thanks a lot Franklin. Smilie
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