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Grep with multiple instances of same pattern


 
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# 1  
Old 08-30-2009
Grep with multiple instances of same pattern

Hi,

This is my text file I'm trying to Grep.

Apple Location Greenland Rdsds dsds fdfd ddsads http Received Return Immediately Received End

My Grep command:

grep only--matching 'Location.*Received'


Because the keyword Received appears twice, the Grep command will stop at the last one:
Location Greenland Rdsds dsds fdfd ddsads http Received Return Immediately Received

I want it to stop after the first one:
Location Greenland Rdsds dsds fdfd ddsads http Received


How is that possible?

Thanks
# 2  
Old 08-30-2009
With awk ...perhaps a solution...

cat file | awk -F "Received" '{print $1,"Received"}'
# 3  
Old 08-30-2009
I don't believe grep is intended to do such a thing, but something like this
Code:
perl -pe 's/.*(Location.*?Received).*/$1/' your_file

can.

edit:
Well i was wrong: grep could, though
man grep says -P --perl-regexp
Interpret PATTERN as a Perl regular expression. This is highly experimental and grep -P may warn of unimplemented features

and in deed, Debian GNU/Linux says:
grep: Support for the -P option is not compiled into this --disable-perl-regexp binary

Last edited by daPeach; 08-30-2009 at 05:23 PM..
# 4  
Old 08-30-2009
Quote:
Originally Posted by protocomm
With awk ...perhaps a solution...

cat file | awk -F "Received" '{print $1,"Received"}'
thanks man, it works!

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