10 More Discussions You Might Find Interesting
1. UNIX for Beginners Questions & Answers
Scheduled job is not running on time.but it is running when executing same command manually.
25 10 * * * /code/bin/ACCOUNT.ksh 1 >/dev/null 2 >&1
Manually executing the same
Ksh -x /code/bin/ACCOUNT.ksh 1 >/dev/null 2 >&1
Added the job to cron tab. (4 Replies)
Discussion started by: Myguest
2. Shell Programming and Scripting
I am writing a script that will eventually be executed by a cron job every 15 minutes. I want to make sure that my logic/script doesn't get executed if a previous job is still running. What would be the best way to handle that scenario? I was thinking to make my script create a temporary... (1 Reply)
Discussion started by: rdogadin
I have removed a cron for particular user , but cron job seems to be running even after the cron entry is removed. The purpose of the cron was to sendmail to user ( it uses mailx utility )
I have restarted cron and sendmail service still user is getting mail alerts from the cron job. And... (4 Replies)
Discussion started by: chidori
I have set up the crontab as follows.
root@IDC4VASAPP07 # crontab -l
0-59 * * * * /var/tmp/r.sh
0-59 * * * * date >> /var/tmp/log
r.sh is as follows.
root@IDC4VASAPP07 # cat r.sh
dt1=$(perl -e 'use POSIX;print strftime... (10 Replies)
Discussion started by: SunilB2011
5. Shell Programming and Scripting
I have this cronjob
* */2 * * * $path/supervisor.sh The supervisor script is checking another script, which initializes the final scripts in multiple directories.
Note that the supervisor script runs without the cronjob.
In each directory, I have the following script:
... (2 Replies)
Discussion started by: TheTransporter
6. Shell Programming and Scripting
I am trying to run a script through contab. The script can only be executed once user logs in as su - oracle. I have tested the script other then cronjob and it executes successfully, more over the paths used in the script are absolute paths.
Crontab entries are as as below.... (3 Replies)
Discussion started by: Asteroid
7. UNIX for Dummies Questions & Answers
I am editing crontab using -e option to add a new job
Below is the line
30 * * * * scriptpath
This job is not executing every thirty minutes.
I have checked, cron daemon is running.
What did I miss? Can some one help?
I am using cron shell..ksh (7 Replies)
Discussion started by: yabhi_22
8. UNIX for Advanced & Expert Users
i have the following line in the crontab
15 5 * * 6 /home/adw/BCE_ADW.pl
The problem is the cron job is not getting started automatically.
But this was working til last week. now it is not working.
what could be the problem. Any idea? (3 Replies)
Discussion started by: Suguna
9. Shell Programming and Scripting
I am facing this problem . My Cronjob entry is not running !!!
I am having Sun solaris 9 and cronjob entry is
"45 1 * * * /safedir/rdns/opt/RDNS1.1Scripts/drpl_audit_log_script.sh_orig > /dev/null 2>&1"
Now when I try to look in the output log files it creates, it is some file with... (1 Reply)
Discussion started by: hkapil
I have a cron schedule like this
04,16,28,40,52 * * * * /nag/startProcessABatch (unix script)
i want to add new lines in this file (like Logging), i just copy this file into a /tmp folder (for backup copy), and i have edited this file (added few lines of code for logging).
... (1 Reply)
Discussion started by: nag_sundaram
SHELL-QUOTE(1) User Contributed Perl Documentation SHELL-QUOTE(1)
shell-quote - quote arguments for safe use, unmodified in a shell command
shell-quote [switch]... arg...
shell-quote lets you pass arbitrary strings through the shell so that they won't be changed by the shell. This lets you process commands
or files with embedded white space or shell globbing characters safely. Here are a few examples.
ssh preserving args
When running a remote command with ssh, ssh doesn't preserve the separate arguments it receives. It just joins them with spaces and
passes them to "$SHELL -c". This doesn't work as intended:
ssh host touch 'hi there' # fails
It creates 2 files, hi and there. Instead, do this:
cmd=`shell-quote touch 'hi there'`
ssh host "$cmd"
This gives you just 1 file, hi there.
process find output
It's not ordinarily possible to process an arbitrary list of files output by find with a shell script. Anything you put in $IFS to
split up the output could legitimately be in a file's name. Here's how you can do it using shell-quote:
eval set -- `find -type f -print0 | xargs -0 shell-quote --`
debug shell scripts
shell-quote is better than echo for debugging shell scripts.
[ -z "$debug" ] || shell-quote "debug:" "$@"
With echo you can't tell the difference between "debug 'foo bar'" and "debug foo bar", but with shell-quote you can.
save a command for later
shell-quote can be used to build up a shell command to run later. Say you want the user to be able to give you switches for a command
you're going to run. If you don't want the switches to be re-evaluated by the shell (which is usually a good idea, else there are
things the user can't pass through), you can do something like this:
while [ $# != 0 ]
case x$1 in
[ $# -gt 1 ] || die "need an argument for $1"
user_switches="$user_switches "`shell-quote -- "$2"`
# process other switches
eval "shell-quote some-command $user_switches my args"
Turn debugging on.
Show the usage message and die.
Show the version number and exit.
The code is licensed under the GNU GPL. Check http://www.argon.org/~roderick/ or CPAN for updated versions.
Roderick Schertler <firstname.lastname@example.org>
perl v5.16.3 2010-06-11 SHELL-QUOTE(1)