Shell Programming and Scripting

Dear experts,
I have this cronjob

Code:

 * */2 * * * $path/supervisor.sh

The supervisor script is checking another script, which initializes the final scripts in multiple directories.

Note that the supervisor script runs without the cronjob.

In each directory, I have the following script:

Code:

#!/bin/sh
for i in *_*.py
do
   if [ -f "${i}_DONE" ]
   then
     continue
   else
     mod9.9 $i && touch ${i}_DONE
   fi
done

the problem is that the cronjob is not running, giving an error

./run01.sh: line 8: mod9.9: command not found

note that without the cronjob, the mod9.9 is running fine from the command line.

Any ideas why?

Use full path to the mod9.9 program in your script.

thanks Bartus, I thought it is not needed for this specific program. I will start my job again and let you know

Thanks!

---------- Post updated at 11:06 AM ---------- Previous update was at 08:44 AM ----------

nice it is working perfectly!

thanks a lot!