how Print previous line ..........

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# 1  
Old 08-04-2009
how Print previous line ..........

HELLO...I wanted to ask you, than sure know unix more than me, as I can obtain the following solution: I have a file with rows of the type:


I would that if in a line is present the word (for example) " CHE " then i can print in video the previous three lines at the word "CHE" obtaining therefore:

As shell i use the KORN SHELL...thanks a lot and sorry for my bad english...
# 2  
Old 08-04-2009
Using ksh, bash, ...
# script
while read line
     case "$line" in
        *" CHE"*) echo "$l1"
                     echo "$l2"
                     echo "$l3"
                     l1=""  l2=""  l3=""

chmod a+rx script
cat somefile | ./script

# 3  
Old 08-04-2009
grep -B3 'CHE' file |grep -v 'CHE'

# 4  
Old 08-04-2009
This should do you:

#  awk '
/ CHE / { for (x=1;x<4;x++){print t[NR-x]}}
' infile

# 5  
Old 08-04-2009
A Perl solution, just for completeness:
perl -ne 'BEGIN{ @a=("","",""); } print @a if /\bCHE\b/; push @a, $_; shift @a;' infile

# 6  
Old 08-04-2009
Originally Posted by johnbach
grep -B3 'CHE' file |grep -v 'CHE'

-B3 is not so usable in all *nix.


- B3, Gnu extension - my quess.
# 7  
Old 08-04-2009
awk -v v="CHE" '{_[NR]=$0}{for(x=0;x++<NF;)if($x==v){for(y=4;--y;) print _[(NR-y)];printf "\n"}}' file

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