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# 8  
Old 08-04-2009
here is the script I wrote :
Code:
#!/bin/bash
stty erase ^H

testlogin()
{
local log=$0
if(test $login != papa);then
exit 1;
fi
}

echo -n "login? "
read login
testlogin $login
echo"still here"
exit 0;

and here is what it give as an output :

Code:
pwd % prout.sh
login?  papa
still here
pwd % echo $?
0
pwd %
pwd %
pwd % prout.sh
login?  azerty
pwd % echo $?
1
pwd %

It seems it is what you want.

You can add password and server as parameter for the function to test them in the same time (maybe rename the function testID then..)

Regards

Last edited by Moumou; 08-04-2009 at 07:15 AM.. Reason: 'a' is missing ...
# 9  
Old 08-04-2009
it never exited because the code DoExit 1 was never executed. Its dependent on some commands's exit code. try playing with them
Code:
echo test || DoExit 1
echo test && DoExit 1

Here's the logic

Code:
exitcode=0 || ignore DoExit1
exitcode!=0 || execute DoExit1


Last edited by ryandegreat25; 08-04-2009 at 08:53 AM..

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