Rename a lot of files using shells script

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# 1  
Old 08-03-2009
Question Rename a lot of files using shells script


This is the list file that i have :

[~/CDR/CSV-FREE-partition-1/20090601]$ ls -la | head -15
total 102
drwxr-xr-x+ 2 Administrators ???????? 0 Aug 3 11:46 ./
drwxr-xr-x+ 28 eindwib mkgroup-l-d 0 Aug 3 11:53 ../
-rwxr-xr-x 1 Administrators ???????? 857 Aug 3 11:46 udr-FREE-SASN-DST-MASTER-R6-partition-1-200906010011+0800-31533.csv.bz2*
-rwxr-xr-x 1 Administrators ???????? 911 Aug 3 11:46 udr-FREE-SASN-DST-MASTER-R6-partition-1-200906010028+0800-31534.csv.bz2*
-rwxr-xr-x 1 Administrators ???????? 588 Aug 3 11:46 udr-FREE-SASN-DST-MASTER-R6-partition-1-200906010043+0800-31535.csv.bz2*
-rwxr-xr-x 1 Administrators ???????? 451 Aug 3 11:46 udr-FREE-SASN-DST-MASTER-R6-partition-1-200906010059+0800-31536.csv.bz2*
-rwxr-xr-x 1 Administrators ???????? 326 Aug 3 11:46 udr-FREE-SASN-DST-MASTER-R6-partition-1-200906010115+0800-31537.csv.bz2*
-rwxr-xr-x 1 Administrators ???????? 422 Aug 3 11:46 udr-FREE-SASN-DST-MASTER-R6-partition-1-200906010135+0800-31538.csv.bz2*
-rwxr-xr-x 1 Administrators ???????? 442 Aug 3 11:46 udr-FREE-SASN-DST-MASTER-R6-partition-1-200906010150+0800-31539.csv.bz2*
-rwxr-xr-x 1 Administrators ???????? 490 Aug 3 11:46 udr-FREE-SASN-DST-MASTER-R6-partition-1-200906010205+0800-31540.csv.bz2*
-rwxr-xr-x 1 Administrators ???????? 299 Aug 3 11:46 udr-FREE-SASN-DST-MASTER-R6-partition-1-200906010225+0800-31541.csv.bz2*
-rwxr-xr-x 1 Administrators ???????? 300 Aug 3 11:46 udr-FREE-SASN-DST-MASTER-R6-partition-1-200906010240+0800-31542.csv.bz2*
-rwxr-xr-x 1 Administrators ???????? 299 Aug 3 11:46 udr-FREE-SASN-DST-MASTER-R6-partition-1-200906010255+0800-31543.csv.bz2*
-rwxr-xr-x 1 Administrators ???????? 301 Aug 3 11:46 udr-FREE-SASN-DST-MASTER-R6-partition-1-200906010310+0800-31544.csv.bz2*
The files is more than this.
I will rename one by one file become like this :

So just change the time stamp 200906 become 200905.
Is it possible using script ?

# 2  
Old 08-03-2009
There should be a better soln.
ls *2009* |while read file
   nf=$(echo $file|sed 's/200906/200905/')
   mv $file $nf

# 3  
Old 08-03-2009
Or use posixshell (ksh, bash,...) builtin replace without external sed.
for file in *200906*
    # example how to check, have we done some change or not - if done, then rename
    [ "$nf" != "$file" ] && mv "$file" "$nf"

# 4  
Old 08-03-2009
Try this...
ls -1 *200906* | sed 's/\(.*\)\(200906\)\(.*\)/mv & \1200905\3/'

if it gives u what u want...

ls -1 *200906* | sed 's/\(.*\)\(200906\)\(.*\)/mv & \1200905\3/' | sh

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