it's urgent ! round number in perl scripting

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# 1  
Old 07-30-2009
it's urgent ! round number in perl scripting

my $number = 12.345673412

I need 3 digits after decimal or after dot(.)

i mean , i need only 12.345

I used int(), ceil(), floor() but it gives me only 12

I need it.

Last edited by Yogesh Sawant; 08-03-2009 at 03:58 AM.. Reason: added code tags
# 2  
Old 07-30-2009
my $number = 12.345673412;
printf( "%.3f\n", $number);

such a basic question cannot be that urgent. Sounds like homework.
# 3  
Old 07-30-2009
Ok. But i want to store the result into that variable.
# 4  
Old 07-30-2009
1. I think you might want to read some perl documentation or a perl book - most especially if this is something you are doing for your work.

2. my $var = sprintf("%.3f", 12.123456);
# 5  
Old 07-30-2009
my $var = sprintf("%.3f", $number);

perldoc -f sprintf
# 6  
Old 07-30-2009
Thanks Smilie
# 7  
Old 07-31-2009
Use patten matching

$number=~ s/([^\.]*\.)(...).*/$1$2/;

---------- Post updated at 01:30 AM ---------- Previous update was at 01:14 AM ----------

Originally Posted by Niroj
$number=~ s/([^\.]*\.)(...).*/$1$2/;
You can also use:

$number=~ s/(\d*\.)(\d{0,3}).*/$1$2/;
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