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it's urgent ! round number in perl scripting


 
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# 8  
Old 07-31-2009
Quote:
Originally Posted by Niroj
$number=~ s/([^\.]*\.)(...).*/$1$2/;

---------- Post updated at 01:30 AM ---------- Previous update was at 01:14 AM ----------



You can also use:

$number=~ s/(\d*\.)(\d{0,3}).*/$1$2/;
No, that does not do any rounding off. If all you wanted to do was truncate the number of digits then substr() is better for that unless you had to search for the number in a string.
# 9  
Old 07-31-2009
Generic, works in every language:
Code:
$number=int($number*1000)/1000;

# 10  
Old 08-03-2009
Quote:
Originally Posted by pritish.sas
my $number = 12.345673412

I need 3 digits after decimal or after dot(.)

i mean , i need only 12.345

I used int(), ceil(), floor() but it gives me only 12

I need it.

Hi Kelvin !

I suggested so, as asked by pritish.
# 11  
Old 08-03-2009
Quote:
Originally Posted by Niroj
Hi Kelvin !

I suggested so, as asked by pritish.
Do you have a question?

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