Executing commands through shell variable

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# 1  
Old 07-23-2009
Executing commands through shell variable

Hey there,
I am trying to pass a command as argument to a function.
The command shows up in $1.
Now I want to execute this command, but if I do a $1

"bla/blaprintf: warning: ignoring excess arguments, starting with `bla/bla'

The code is :


fn 'printf "bla/bla bla/bla bla bla bla bla\\n"'

Any ideas how to get it work please ?
# 2  
Old 07-23-2009

There is nothing wrong with your function.

The error
"bla/blaprintf: warning: ignoring excess arguments, starting with `bla/bla'

shows that the printf did run.

I get a different output:
/root/tmp/test # ./sample
"bla/bla/root/tmp/test #

But there's nothing wrong with your thinking. i.e.
/root/tmp/test # cat sample
fn ls
/root/tmp/test # ./sample
a  b  blah  c  file1  file2  sample  tst
/root/tmp/test #

The problem you might be seing is with your printf itself.
# 3  
Old 07-23-2009


eval "$1"

# 4  
Old 07-24-2009
That would work!
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