Shell Programming and Scripting

Hi All,

I am trying to update files placed in a folder to another directory structure, where that file pre existed. There are n directories so i have to search in every directory and where ever file exists need to replace it.

Problem faced:
1)Directories have files with name as xyz.class and abc$xyz.class (this is naming convention in java for inner classes). But when i simply grep xyz.class it gives me both which is not required only xyz.class is required

I want to know is there any command or way which treats these file names as complete one string name.
command use now : jar -tvf old_jarfiles/$jarname | grep "\<$fntoreplace\>"

Try this with grep:

Code:

grep -w '^xyz.class'

Check the man page for the used option.

Code:

fntoreplace="xyz.class"
 jar -tvf old_jarfiles/$jarname | grep "^$fntoreplace"

Thanks for reply!!! I got to solve his by

jar -tvf sc.jar | grep "\<AudioTrack.class\>"

but my concern is to know how to grep files with $ sign
e.g
jar -tvf sc.jar | grep "\<ShutdownController$ShutdownHandler.class\>"

in real time it will be
jar -tvf sc.jar | grep "\<$fntoreplace>" [where fntoreplace contains $ sign in their name]

You first question ask about to find the target file in the n directotries.
That can due with "find" and "sed" on unix command.

But the second statement show that you use grep from the list inside the jar file. So the solution is find the target from the list from the jar,isn't it?

If I am correct it means you want to find the path reference of the target class file AudioTrack.class, ShutdownController$ShutdownHandler.class
that listed in the jar file.

I also assume that you know all you target class file names.

Please try this.

1. create a a_class_file file content the list of .class file name that you want to find from the jar file.

2. You will then create a script file. For example jar_file.sh consist of command as belowing:
#!/bin.sh
for i_class in `cat a_class_file`
do
jar -tvf sc.jar | grep "\<$i_class\>"
done

Run the script jar_file.sh to get the result.
$ sh ./jar_file.sh

Hope this can help

Yeah you are right tom_cmu. I am using the same thing in my script.

Pls. find more insight on problem :
Suppose i have two jars
Jar1 contains xyz.class , xyz$abc.class, aaa.class
Jar2 contains abc.class bbb$xyz.class, bbb.class and so on.

Queries are ---

1) At runtime if i search for abc.class in jar1 it returns true, because of xyz$abc.class which is incorrect.
It should return true only for jar2 which has file with name abc.class

2) If i have to search for file xyz$abc.class in jar1 how to do that with grep. As grep takes $ as special symbol and i cannot put \ in front of $ to suppress it in variable which contains its name.

Is there way in awk or sed to implement this

Hope I am more clear in stating problem this time. Your reply will be helpfull

snippet of script made is .....

for file in new_files/*.class
do
if [ -f $file ]
then
fntoreplace=`echo $file | cut -d "/" -f2`
echo $fntoreplace
jar -tvf old_jarfiles/$jarname | grep "\<$fntoreplace\>"

- - - - - -

I guess the text that come out from jar -tvf looks like these.
<abc.class> , <xyz$abc.class>
if so why don't you try this:

jar -tvf old_jarfiles/$jarname | grep "^<$fntoreplace"

If I do a wrong guess. There is the way to put "\" in front of "$" before the text feed through the grep command as:

jar -tvf old_jarfiles/$jarname | sed 's/\$/\\$/' | grep "\<$fntoreplace\>"