Shell Programming and Scripting

Can someone please shed light on why this may not be working, file does exist, but I get an error


if [[ ! -f `${source_path}/${file_mask}` ]]
then
echo "No ${source_path}/${file_mask} found - ">> ${logfile}
result=1
check_result ${result} "Failed to find file ${source_path}/${file_mask}"
fi


source_path=$HOME/xxxx
file_mask=iamafile_[0-9][0-9][0-9]_[a-z].dat

Many Thanks

Which error?

[ code ][ /code ] tags (sans the spaces) help to keep source code and other listings readable (especially indentions, like this)

Code:

source_path=$HOME/xxxx
file_mask=iamafile_[0-9][0-9][0-9]_[a-z].dat

 if [[ ! -f "${source_path}/${file_mask}" ]]
       then
                echo "No ${source_path}/${file_mask} found - ">> ${logfile}
                result=1
                check_result ${result} "Failed to find file ${source_path}/${file_mask}"
       fi

The (probable) problem was that you used backticks when there was no command to be executed. Use double quotes instead.

Thanks Pludi.

I tried that as well, but that does not interpret the filename i.e. it tests to see if $HOME/xxxx/iamafile_[0-9][0-9][0-9]_[a-z].dat exists rather than $HOME/xxxx/iamafile_111_b.dat

Thanks in advance

If it checks for a file named "iamafile_[0-9][0-9][0-9]_[a-z].dat", you've disabled globbing somewhere or are using one weird kind of shell, because this is a valid file pattern which should match any file from iamafile_000_a.dat to iamafile_999_z.dat

this can work ( not tested)

and use double quotes in test command.