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I dont think to kill a process you need a script.

This can be done using kill command.

if your input is symmetric.. i.e blah blah is always the second column then CUT should be a better option.

Please confirm if this is the case. If so,


cut -d"," -f2 <input_file> >...

This is one way you can do it:

Create a XML template and store it having unique variable names [ for ones you want to replace the values with ].

Read this template.
Replace the variables...

this will work...

if [[ "$1" = "WO_STMT_05292009" || "$1" = "WO_BENE_STMT_05292009" ]]
then
echo "correct"
else
echo "error"
fi

is this what you want?


date +"%0m/%0d/%y"

redirect it /dev/null

strange...

Ok do this

echo $line | grep -i "PATTERN"
if [ $? -eq -0 ]
then
bla bla
else
bla bla
fi

you can do some thing like this:

if `echo $line | grep -i "PATTERN"`
then
bla bla
else
bla bla
fi

this works in KSH.

You can do this way:


# echo "Shubhendu" | awk '{print substr( $0, 3, 3 )}'
bhe
#


:b:

if I get your question right... then you need to read the extn of all the files? Am I correct?

If so, above code will be of less help.

You can try this:


var1=abcd.xyz
var2=$(echo...

You welcome.

This code will delete blank lines from the file:


sed '/^ *$/d' <file_name>


you can either PIPE this or redirect this to a tmp file and do next operation accordingly.
...

for 2> you need to have a loop say if loop which will check for value of capacity... if 50 or more then take action else no action.

:b:

ok, if I get it right try this:

sed -n '2,6p' <file_name>

this will print lines starting at column 2 to 6.

Substitute 2 & 6 with your loop variables.

let me know if you need more on...

Simple way to do it:


head -10 <file_name> | tail -5


what this peice of code is trying to do is: get top ten lines of the file and print last five of those to STD output. you can keep...

just a minor change in above code...


gsub("#"," ",tochange)


:p

you may use this...


find [SEARCH_PATH] -type f -size +[MEG_BYTES]000000c


:b:

use this

sed '/\.tk *$/d' dat_file.txt > temp.txt

you need to replace the . with \. in order to remove its special usage.

Prabhu,

you can do it in two ways:

1> If you have to write the file name in single line then you need to cut each file name before you add the time stamp.

you can try some thing like this...

rsh server1 cat /home/test.txt |sed s/01-jun-2009/01-aug-2009/ |sed s/ABCD/1234/

this will work... just remove the <" ">

More over if you want to replace data more then one place in the file...

Can you provide some sample input, and yeah what have you tried so far....

looks like a homework question....

this is against the forum rules :cool:

Check out Perderabo's post.

https://www.unix.com/answers-frequently-asked-questions/13785-yesterdays-date-date-arithmetic.html

Can you show what you have tried so far?

x=1
var="abc$(printf ${x})"

echo $var

abc1
:b:

period=`cut -d"=" -f2 file.txt | cut -d " " -f2`
name=`cut -d"=" -f3 file.txt | cut -d " " -f 2,3`
dest=`cut -d"=" -f4 file.txt`

# echo $period
20090531
# echo $name
Clayton Lumbar
# echo...