Variable inside a variable


 
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# 1  
Old 06-02-2009
Variable inside a variable

Hi,
here is the problem description...

X=1
var${x}=abc
echo ${var${x}}

It is not working...Smilie
Is there any solution..


Thanks,
Swat
# 2  
Old 06-02-2009
try this

x=1
var="abc$(printf ${x})"

echo $var

abc1
Smilie
# 3  
Old 06-02-2009
Swat - uppercase X and lowercase x are not the same variable.

Using bash
Code:
$ X=1
$ eval var${X}=abc
$ echo $var1
abc
$ ref="var"${X}
$ echo $ref
var1
$ echo ${!ref}
abc

Using ksh93
Code:
$ X=1
$ eval var${X}=abc
$ echo $var1
abc
$ nameref ref="var"${X}
$ echo $ref
abc
$

 
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