UNIX for Dummies Questions & Answers

Hi,

I have to grep a word 'XYZ' from 900 files ( from 2007 till date), take its count month wise. The output should display month, count , word 'XYZ' .
I tried searching the forum for solution but could find any.
I would apprieciate if any one can help me asap ....

Many Thanks

Can you show what you have tried so far?

can anyone help please ....

check the man page of grep. don't be lazy

I appreciate your response ...

I am not lazy bro ..i am searching whatever i can .. i temporarly got what i want but i want get it done through proper script ..
right now i have used

cat /path/*filename* |grep 200810 |grep XYZ |wc -l

but its not getting the compressed files count and i have to maunaly copy this date in notepad..

if i could get the count, month from a single command line it would be great ...

Heyo,
how about structure of your files? Maybe, if it isn't so secret, just a little pattern of few lines to copy-paste here, so I can better see what you mean ynd try it on my machine. If you mean to number lines then try grep -n, if something else - I need more info on the subject.

contents of the file is like below... there are thousands of such records in a file. it may be value for Order_Type can be either XYZ or ABC...i get these file daily .. Thanks mate for responding

<ORDER Date_Format="YYYYMMDDHH24MISS" Line_Ref="4444455" Action_Date="20090309000000"><CUSTOMER_INFO Customer_Ref="423555577" Job_No="3051908"/> <PRODUCT_INFO Type="WC"/><WC Billing_Destination="CM" Order_Type="XYZ" Main_CLI="544444444444"/></ORDER>
</ORDERS>

<ORDER Date_Format="YYYYMMDDHH24MISS" Line_Ref="4667455" Action_Date="20090309000000"><CUSTOMER_INFO Customer_Ref="234442357" Job_No="2055688"/> <PRODUCT_INFO Type="WC"/><WC Billing_Destination="CM" Order_Type="XYZ" Main_CLI="99844444444"/></ORDER>
</ORDERS>