putting numbers behind eachother

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# 1  
Old 09-19-2011
Error putting numbers behind eachother

I want to make a program where you have to insert binary numbers like this:

iBinary = getche(); 
}while(iBinary == 1 || iBinary == 0);

after you get the numbers I want them to be placed behind eachother so you will get:



I really need some help with it because I dont know how to do it.
# 2  
Old 09-19-2011
Have you considered firstly storing them in a char array and then printing them out.
# 3  
Old 09-19-2011
can you explain it to me :P
I've considered using chars but not really sure how to use it.
I still need to do a calculation with the whole value.
# 4  
Old 09-19-2011
To make an array:

char buf[10];

To put something in it:


For an array of 10 elements, you should use elements 0 through 9 inclusive.

UNIX doesn't have "getche". Try 'getc'. Unless you put your terminal in noncanonical mode, it will wait until the user presses enter to receive data.
# 5  
Old 09-19-2011
ok got that but how can i get them behind eachother.
lets say i get this
buf[0] = 1
buf[1] = 1
buf[2] = 0
buf[3] = 1

to this

value = 1101
# 6  
Old 09-19-2011
An array of characters is a string. Stick a '\0' on the end and you can print it just like that with puts, printf, and so forth, as well as strcpy it, etc.
#include <stdio.h>

int main(void)
        char buf[10];
        int pos=0;

        while(pos < 9)
                int c=getc(stdin);
                if(c < 0) break; // End of file
                if(c == '\n') break; // end of line

                if((c < '0') || (c > '1')) continue; // Ignore everything but 0/1
                buf[pos]='\0'; // NULL terminator

        printf("You typed:  %s\n", buf);

This User Gave Thanks to Corona688 For This Post:
# 7  
Old 09-19-2011
thank you so very much
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