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Getting what error?

Try this to get the concept...

[root@bt] $ cat run
#!/bin/bash

set -- "1" "2" "3" "4" "5"
echo $*
shift
echo $*
shift
echo $*
shift
echo $*
Output

[root@bt] $ ./run
1 2 3 4 5
2 3...

When you say the files are getting created monthly basis, does it mean that each file created every month? or all of them created at once one for each month?

--ahamed

If the files maintain the timestamp then try this...
ls -t Test_Directory/FILE* | tail -1 | xargs -I {} mv {} /your/destination
--ahamed

Instead of copying and removing .. just move the file to the destination path ..

$ ls File* | sort -n | nawk '{if(NR==1) {print "mv "$0" /dest/path"}}' | sh

Try this...
#!/bin/bash
day=$(date +%d)
month=$(date +%m)
year=$(date +%Y)
run_or_not=$( awk -v day=$day -v month=$month -v year=$year 'BEGIN {
if(month%2 && day == 30){ print "run"...

Assuming the modification time of the directories is reliable to sort out the latest:

set -- $(ls -t)
shift
rm -r $*
If the "latest" directory is last in the sorted output of directory names,...

You could have a script in crontab, that just does the following:

L=$(cal| awk 'END {print $NF}')

Then compare the actual day with $L and decide to run your job or not.
It will run every day...

https://www.unix.com/shell-programming-scripting/19318-crontab-entry-run-every-last-day-month.html

What your awk is doing doesn't seem to fully match what your input file looks like (i.e. you're using | as a field separator, when the path is / separated, there is nothing ending with ".atr" - since...

mkdir "$(echo "/user/Oracle/my_catalog/default/root/webcat+backup+testing+07192011.atr" |\
awk -F\| '{gsub(/(+)/," ",$NF);gsub(/\.atr$/,""); print}')"

file_path=" /user/Oracle/my_catalog/default/root/webcat+backup+testing+07192011.atr"
dir_name=`echo $file_path | awk -F"[.+]" '{print $NF-1}`
mkdir $dir_name

I suppose you need something like this:

while read eachline
do

VAL=$(
printf '%s\n' "$eachline" |
sed -e 's/[^/]*$//' -e 's/default/default_new/'
)

cp -r --...

Try this:


echo $eachline | dirname | sed 's:/backup/:/backup_path/:'

sed 's/[^/]*$//' -e 's/backup/backup_new/' filename

$> VAR=user/oracle/Test_admin/myfolder/bakup/part_bkptemp_part_bkp_repeated/list.txt
$> echo ${VAR%/*}"/"
user/oracle/Test_admin/myfolder/bakup/part_bkptemp_part_bkp_repeated/

or

$>...

dirname



$ dirname "a/b/c.txt"
a/b

awk -F"/" '{print $(NF-1)}' file

$nawk -F"\/" '{print $NF}' test
adhoc
new
test



---------- Post updated at 02:43 PM ---------- Previous update was at 02:42 PM ----------


$while read line; do basename $line; done <...

if the format of the lines does not change this may help you..
name=`cat <filename> | awk -F '/' '{ print $7}'`
echo $name

or else to print the last word try this
name=`cat <file name> | awk...

Hi
Just a backslash missing in your original sed:

sed 's/.*\/\(.*\)/\1/' list.txt

Guru.

You could perform a check to see if the file exists


while [ -x /usr/x/x/x/temp_part_bkp/$Eachline ] ; do
$Eachline="$Eachline.1"
done;