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Shell Programming and Scripting

get last word from each line

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# 1  
Old 06-30-2011
get last word from each line
Hello Experts,

I have requirement where a file consist of multiple lines...some sample of lines are ...
Code:
/usr/local/Oracle/shared/admin/adhoc
/usr/local/Oracle/shared/admin/new
/usr/local/Oracle/shared/admin/test

I want to get all my last word "adhoc new test"
Code:
sed 's/.*/\(.*\)/\1/' list.txt

but giving error
Code:
sed: 0602-404 Function s/.*/\(.*\)/\1/ cannot be parsed.

its failing


Please help me
Smilie
Thanks for all your support and help
Last edited by Franklin52; 06-30-2011 at 01:02 PM.. Reason: Please use code tags, thank you
# 2  
Old 06-30-2011
Code:
 
$nawk -F"\/" '{print $NF}' test
adhoc
new
test

---------- Post updated at 02:43 PM ---------- Previous update was at 02:42 PM ----------

Code:
 
$while read line; do basename $line; done < test
adhoc
new
test

This User Gave Thanks to itkamaraj For This Post:
aks_1902
# 3  
Old 06-30-2011
if the format of the lines does not change this may help you..
Code:
name=`cat <filename> | awk -F '/'  '{ print $7}'`
echo $name

or else to print the last word try this
Code:
name=`cat <file name> | awk -F '/'  '{ print $(NF)}'`

Last edited by Franklin52; 06-30-2011 at 01:03 PM.. Reason: Please use code tags, thank you
This User Gave Thanks to gowtham.varma For This Post:
aks_1902
# 4  
Old 06-30-2011
Hi
Just a backslash missing in your original sed:

Code:
sed 's/.*\/\(.*\)/\1/'  list.txt

Guru.
This User Gave Thanks to guruprasadpr For This Post:
aks_1902
# 5  
Old 06-30-2011
Thanks Guru...thanks for all your help and everyone cheers
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