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You could try with eval. This method should be deployed with care; you should know EXACTLY what you are evaling as you may end up running unwanted or even malicious code without control of it.

Are $2 and $3 supposed to be filenames or space separated parameter lists?

Here is one bash solution using the -v option of printf:

#!/bin/bash
function csvdiff {
if [ "$1" == "-s" ] ;...

Try IFS="" read -r separator

uuencode is extremely old, mail clients are beginning to not understand it. I would try sending to a different email client first, to make sure it's actually going wrong, rather than just being...

Perhaps ed or ex would be simpler:
ed -s file <<-"EOF"
g/Mamma/.-1,.+1d
1,$p
EOF
And, if you want to modify the input file instead of just print the file contents with the specified lines...

...and is there a question, comments or just a code dump waiting for a miraculous response answering your unexplained issue?

This is fine - the only issue might be for maintenance, someone unfamiliar with sed would have issues learning what the code really does.

In the case where you need to reverse the words in a...

Hi, use quotes around the first EOF
cat > "$1/$2.sh" << "EOF"
#! /bin/bash
ant -q -buildfile $HOME/$3/build.xml $4
...
EOF

It's a good example of arrays. Whether arrays are actually needed here is the question.

Novice programmers tend to store entire documents:

# Store every line
while read LINE
do
...

Nice Subbeh. It is better to add parentheses, since some awks regard the comparison as ambiguous:
awk '{print ($1<$2)?$1:$2}' file
or
awk '{print ($1<$2?$1:$2)}' file

Sorry, that is incorrect. Doing that will truncate the file before awk is finished reading it, throwing away most of its contents.

Even things like sed -i actually use temporary files to store...

In addition to what has already been said, you're not looking for a field separator, you're looking for a field fill character. There are several ways to do this, here are two:
awk...

Because it would be syntactically incorrect. You could however do this:
set -A array $(
cat << EOF
val1
val2
val3
EOF
)

Elementary. [^#] will match one character which is not an octothorpe (or hash). So, what you are asking grep to match is one non-hash character (mandatory for the overall pattern to match) at the...

[^#] means a single character that is not a hash-sign.
Why not use:
grep '^2013-12-31'
But perhaps you mean this:
grep '^[^#]*2013-12-31'

If you check out sdiff using strace/truss/tusc, you can see where it goes wrong. This tool is very educational, turn on all the local options, and learn! Probably, it does seeks and so gets upset...

Well, it could tell you if, for example, either function returns an error:


$ cat myScript
Func1() {
return $1
}

Func1 1
retval=$?
Func1 0
echo $(($?|$retval))

Func1 0
retval=$?...

The double bracket is used in bash for arithmetic expansions. thus $((x|y)) is a bitwise OR of the numeric values in $x and $y

It is bitwise "OR" operator. Check this link: Linux Shell Scripting with Bash > Expressions > Bitwise Operations - Pg. : Safari Books Online...

use set -f


$ set -f; for f in $files ; do echo $f ; done
/tmp/test/*file1
/tmp/test/*file2
/tmp/test/*file3
/tmp/test/*file4

Well, the set -f option mentioned by elixir_sinari is a quick way.to do that (and it works for me in KSH88 on AIX)

One way:
files=' /tmp/*file1 /tmp/*file2 /tmp/*file3 /tmp/*file4'
set -f
a=($files)
set +f...

It is probably a "best practices" convention in your shop. It may not be a best practice in reality.

In bash: typeset, when applied as in your example, prevents parameter substitution from being...

Please check this (https://www.unix.com/shell-programming-scripting/204783-capture-specific-fields-file.html#post302721125)

Just replace s with a[$3] here:)

awk '{x=x+$1};END{printf("%.2f\n", x)}' testfile