Shell Programming and Scripting

Hi,

I am trying to create a shell script b.sh inside a shell script a.sh.
Now, i need to execute the command inside b.sh on another server and pick the values of that server. But i am unable to do the same.

(snippet of code)

Code:

  cat > "$1/$2.sh" << EOF
#! /bin/bash
ant -q -buildfile $HOME/$3/build.xml $4

Now what i need is when b.sh is created, it should have the same text inside it.
But what is happening is it is replacing $HOME , $3 and $4 when a.sh is executed.

Example:
b.sh has
ant -q -buildfile /root/work/build.xml 2

whereas it should have
ant -q -buildfile $HOME/$3/build.xml $4

Please let me know how to do this?

Hi,
Use back slash before $

Code:

ant -q -buildfile \$HOME/\$3/build.xml \$4

Hi, use quotes around the first EOF

Code:

cat > "$1/$2.sh" << "EOF"
#! /bin/bash
ant -q -buildfile $HOME/$3/build.xml $4
...
EOF

Thank you prav_chidugulla, i was able to solve the issue.
Thank you Scrutinizer, although i didnot try your way, but thanks for your time..