directory -l filename perl


 
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# 1  
Old 02-12-2009
directory -l filename perl

Can anybody let me know what following commands will do in perl

1.my $result = `/main/home/bin/iwex -l '$File1'`;
2.my $setcmd = "/main/home/bin/iwex -s \"$File2\" \"$File3\"";
where $File1 $File2 $File3 are regular files.


Please suggest something.
Ur welcome
# 2  
Old 02-12-2009
it looks like it runs the iwex utility and returns the results of whatever that utility does. I have no idea what that is though.
# 3  
Old 02-12-2009
Thanks kevin.
Can u please give more idea about iwex with example.
# 4  
Old 02-12-2009
Your first line will take the output of the command '/main/home/bin/iwex -l $File1' (with the value of $File1 substituted) and assign it to the variable $result. The second line will assign the string '/main/home/bin/iwex -s "$File2" "$File3"' (with the values for $File[23] substituted) to the variable $setcmd.
As for what the iwex program does: best to ask the person that developed/deployed it.
# 5  
Old 02-12-2009
Quote:
Originally Posted by millan
Thanks kevin.
Can u please give more idea about iwex with example.
I guess you didn't understand when I said: "I have no idea what that is though." Let me clarify..... I have never heard of iwex, I have no idea what iwex is, I can not give you an example of what iwex is or does.

Do you know how to use google? Try searching for iwex. Smilie
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