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How to read those files and output to base?

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# 1  
Old 10-22-2007
How to read those files and output to base?
Hi,

HTML Code:
-rwxr-xr-x  1 abc mkpasswd 2483 Oct 20 15:42 0132200710-ps5_cdrm.unl
-rwxr-xr-x  1 abc mkpasswd 1826 Oct 20 15:43 0132200710-ps5_cdrn.unl
-rwxr-xr-x  1 abc mkpasswd 1788 Oct 20 15:44 0132200710-ps5_cdro.unl
-rwxr-xr-x  1 abc mkpasswd 1681 Oct 20 15:44 0132200710-ps5_cdrp.unl
-rwxr-xr-x  1 abc mkpasswd 1373 Oct 20 15:45 0132200710-ps5_cdrq.unl
-rwxr-xr-x  1 abc mkpasswd 1371 Oct 20 15:45 0132202469-ps5_cdrm.unl
-rwxr-xr-x  1 abc mkpasswd 1559 Oct 20 15:46 0132202469-ps5_cdrn.unl
-rwxr-xr-x  1 abc mkpasswd 2121 Oct 20 15:47 0132202469-ps5_cdro.unl
I have list of files as above for eg, I wanted to have my end output result for all
0132200710*unl to be in one single file, and all 0132202469*unl and so forth..

Please help.
# 2  
Old 10-22-2007
check the cat man page.
# 3  
Old 10-22-2007
You can do something like that :
Code:
ls *-*.unl | \
while read file
do
   root=$(echo $file | cut -d- -f1)
   cat $file >> $root.unl
done

Jean-Pierre.
# 4  
Old 10-22-2007
With zsh:
Code:
set -- *unl
for f (${(u)${@%-*}}) print -rl "$f"*>"$f"_all

Otherwise:
Code:
for f in *unl;do printf "%s\n" "$f">>"${f%-*}"_all;done

# 5  
Old 10-22-2007
hey just try,
ls -1 <<search pattrn>>*unl >> filename.txt
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