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# 1  
Old 09-29-2009
Java change

bh,lg.yu.,fgh,ry,.tyl,tyk,ty,ty,ty,.

Last edited by frankycool; 10-21-2009 at 09:46 AM..
# 2  
Old 09-29-2009
What have you done so far? What is the problem that you're having? Most folks around here are happy to help but generally not willing to do the work for you.
# 3  
Old 09-29-2009
Although homeworks are not allowed on this site, we could help if you show us what you have tried so far. Have a look at the while/break/done structure as well as the read function.
# 4  
Old 09-29-2009
Java Hi guys this is what i have done so far

Code:
#!/bin/bash

  read -t 10 -p "Code : " code
  if [ "$code" == "boom" ]; 
  then
       echo "Bomb Disactivated"
  else
       echo "Booom!!"
  fi


(Now what i cant do is the 3 tries validation entry of the secret code)

Last edited by Franklin52; 10-02-2009 at 04:43 AM.. Reason: Please use code tags!
# 5  
Old 09-29-2009
you could use a C-style for loop:
Code:
for (( i=1 ; i<=3 ; i++ )); do echo $i; done
1
2
3

# 6  
Old 09-29-2009
There are two things, the number of tries and the running clock. The -t option of the read internal command takes care of the timout while the shell wait for the user input.

But you have to implement a general timer that will start as soon as the script starts. For that, use the date function converted in number of seconds since EPOCH. That's the idea. Try this:

Code:
#!/bin/bash
time=60
tries=3
start=$(date +%s)

left=$time
while true;do
    read -t $left -p "Code: " code
    ((tries--))
    left=$(($time-$(date +%s)+start))
    if (( $left<=0 || $tries==0 ));then
        echo "BOOOOM"
        break
    fi
    if [[ "$code" == "boom" ]];then
        echo "Correct. Bomb defused"
        break
    else
        echo "Wrong. Try again. There are $left seconds and $tries tries left."
    fi
done
exit

And.. please use the CODE tags for clarity.

Last edited by ripat; 09-29-2009 at 01:14 PM.. Reason: some fixing
# 7  
Old 10-02-2009
Thanks Ripat i am going to try this code now

---------- Post updated at 03:57 PM ---------- Previous update was at 01:46 PM ----------

Ripat your code worked like magic !!Thank and Problem solved Smilie

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Test Your Knowledge in Computers #666
Difficulty: Medium
IEEE 802.3 is a working group and a collection of Institute of Electrical and Electronics Engineers (IEEE) standards produced by the working group defining the physical layer and data link layer's media access control (MAC) of wireless Ethernet.
True or False?

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