Unix File name manipulation

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Operating Systems AIX Unix File name manipulation
# 1  
Old 09-29-2011
Error Unix File name manipulation

I need a script that will raname the following file names that beging with 08078* in unix as follows:

Rename 08078-08201103-H00044-CA.835
as follows:


Bascially it will do this:

1) Keep the first 6 positons.
2) Move the yr from the file name to be the first after the first hyphen
to be like this 110820 "yymmdd"
3) Remove the 03 after 11 in the file name so the final file name is 08078-110820-H00044.CA.835

Please let me know as soon as possible. I am pressed for time and hope to have an anser to today if possible. Thank you
# 2  
Old 09-29-2011
What have you tried so far & where are you stuck? This is a help and support forum, not a solution-by-demand site.
# 3  
Old 09-30-2011

I figured it out on my own after I posted this. It is working. Here is how I did it:

I have files coming like this: 08101101.wsp ...etc I finally got it to work to write out the file per specs as:

and her is the code I came up with and it works:
#First loop to add 08078 at the begining of the file and and H00044-C.835 # at the end:
for file in $GetFileName*.*; do
     newfile=`echo 08078-$file-H00044-C.835`
     mv $file ./$newfile
# 2nd For loop to only keep one extention on the file name
for file in 08078-*.835; do
     newfile=`echo $file | awk -F'.' 'BEGIN{OFS=""}{s=$NF;o=$0;$NF="";print "mv "o" " $0"."s}'|sh`
# 3rd For loop to re-arrange how to rename the file:
for file in 08078-*.835; do
     GetNumb=`echo $file  | cut -c1-5`
     Getmmdd=`echo $file  | cut -c7-10`
     GetYear=`echo $file  | cut -c11-12`
     GetSeq=`echo $file   | cut -c13-15`
     GetIns=`echo $file   | cut -c19-24`
     GetChar=`echo $file  | cut -c26-26`
     GetRest=`echo $file  | cut -c 27-`
     mv $file ./$NewFile

It works for what I want it to do. Is there a better way to do this "Maybe with one for loop vs. 3 loops ?


Moderator's Comments:
Mod Comment Please use code tags

Last edited by zaxxon; 10-10-2011 at 05:26 AM.. Reason: code tags, see PM
# 4  
Old 10-07-2011
#! /usr/bin/ksh

ls | grep "^08078" | while read org_name ; do
        print "Org name  : $org_name"

        ## Split filename in separate parts





        ## Split Date in Year Month and Day



        ## Define new name
        print "New name  : $pre-$year$month$day-$string$code.$post"

Org name  : 08078-08201103-H00044-CA.835
New name  : 08078-110820-H00044CA.835

# 5  
Old 10-07-2011

Thank you
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