Variable passing Post: 96974

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passing a variable inside a variable to a function

I would like to know how to pass a variable inside a variable to a function. sample code below -------------- for x in 1 9 do check_null $C$x ##call function to check if the value is null if then echo "line number:$var_cnt,...

2. Shell Programming and Scripting

passing a variable inside another variable.

Any help would be great. I know this is a dumb way of doing this, but I would like to know if there is a solution doing it this way. I'm very new at this and I'd like to learn more. Thanks! :D:D count=0 while ; do echo "enter your name" read name_$count let count=count+1 done ...

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Hello, I am new to shell (i.e. linux bash) programming and have the following question: When using this wget command I can download a certain website that needs login information by passing a previously acquired cookie: wget --header='Cookie: SID=ac658ef0876b24ff456' somewebsite.comAs...

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Passing variable as input & storing output in other variable

I have a below syntax its working fine... var12=$(ps -ef | grep apache | awk '{print $2,$4}') Im getting expected output as below: printf "%b\n" "${VAR12}" dell 123 dell 456 dell 457 Now I wrote a while loop.. the output of VAR12 should be passed as input parameters to while loop and results...

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Passing a variable via ssh, can't quite get it right

Hi Guys n Girls, Below im using a while command to wait for a file on another server then carrying on with the script..... I dont believe the $Sausage1 variable is being passed to the other server so its not finding the file. If i replace the variable with the date then it works as expected. ...

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makesh

MAKESH(1)						      General Commands Manual							 MAKESH(1)

NAME

       makeSH - a .SH script maker

SYNOPSIS

       makeSH files

DESCRIPTION

       MakeSH  examines  one or more scripts and produces a .SH file that, when run under sh, will produce the original script.  The .SH script so
       produced has two sections containing code destined for the output.  The first section has variable substitutions performed  on  it  (taking
       values  from  config.sh), while the second section does not.  MakeSH does not know which variables you want to have substituted, so it puts
       the whole script into the second section.  It's up to you to insert any variable substitutions in the first section for any values you want
       from config.sh.

       You  should  run  makeSH from within your top-level directory and use the relative path to the file as an argument, so that the "Extracting
       ..." line printed while running the produced .SH file later on will give that same path.

AUTHOR

       Larry Wall <lwall@netlabs.com>

SEE ALSO

       pat(1), metaconfig(1), makedist(1).

BUGS

       It could assume that variables from metaconfig's Glossary need to be initialized in the first section, but I'm too lazy to make it do that.

								       LOCAL								 MAKESH(1)

10 More Discussions You Might Find Interesting

1. UNIX for Dummies Questions & Answers

passing a variable inside a variable to a function

Discussion started by: KingVikram

2. Shell Programming and Scripting

passing a variable inside another variable.

Discussion started by: reconflux

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Passing Variable in sed

Discussion started by: saifurshaon

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Passing a wildcard in a variable

Discussion started by: jimbojames