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# 1  
Old 06-09-2011
Passing variable to awk

Hi,
I'm new with this stuff, but I hope you can help me.

This is what I'm trying to do:

for id in $var; do

awk '{if ($1 == $id) print $2}' merg_data.dat > neigh.tmp


done


I need that for every "id", awk search the first column of the file merg_data.dat which contains "id" and print the second column to the file neigh.tmp

The problem is that writing $id in the awk command seems not working ...

Suggestions?
# 2  
Old 06-09-2011
read the man page of awk. There is a -v option to pass the shell variables to awk.

Give it a try :-)
# 3  
Old 06-09-2011
Please use code tags.
-v options works like this:
Code:
for id in $var; do
    awk -v i=$id '{if ($1 == i) print $2}' merg_data.dat > neigh.tmp
done

Or using awk's condition{action} semantics:
Code:
awk -v i=$id '$1==i{print $2}'

# 4  
Old 06-09-2011
thanks, now it works!

Smilie

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