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Top Forums Shell Programming and Scripting Removing carriage returns with sed Post 96698 by aigles on Monday 23rd of January 2006 03:24:26 AM
Old 01-23-2006
== is no'nt a valid operator but some implementations accep it.

You can also use case statement :

Code:
#! /bin/ksh

while read line
do
        case "$line" in
        *Group*)
                GROUP=${line##*=}
                ROLE=""
                USER=""
                ;;
        *Role*)
                ROLE=${line#*=}
                ROLE=${ROLE%% *}
                USER=""
                ;;
        *User*)
                USER=${line##*=}
                [[ -n $GROUP && -n $ROLE && -n $USER ]] && echo "$GROUP,$ROLE,$USER"
                ;;
        esac
done < $1

Jean-Pierre.
 

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CREATE 
GROUP(7) SQL Commands CREATE GROUP(7) NAME
CREATE GROUP - define a new user group SYNOPSIS
CREATE GROUP name [ [ WITH ] option [ ... ] ] where option can be: SYSID gid | USER username [, ...] INPUTS name The name of the group. gid The SYSID clause can be used to choose the PostgreSQL group id of the new group. It is not necessary to do so, however. If this is not specified, the highest assigned group id plus one, starting at 1, will be used as default. username A list of users to include in the group. The users must already exist. OUTPUTS CREATE GROUP Message returned if the command completes successfully. DESCRIPTION
CREATE GROUP will create a new group in the database installation. Refer to the Administrator's Guide for information about using groups for authentication. You must be a database superuser to use this command. Use ALTER GROUP [alter_group(7)] to change a group's membership, and DROP GROUP [drop_group(7)] to remove a group. USAGE
Create an empty group: CREATE GROUP staff; Create a group with members: CREATE GROUP marketing WITH USER jonathan, david; COMPATIBILITY
SQL92 There is no CREATE GROUP statement in SQL92. Roles are similar in concept to groups. SQL - Language Statements 2002-11-22 CREATE GROUP(7)
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