My program:
__________________________________
#!/bin/ksh
DAY=`date +%y%m%d`
H=`date +%H`
M=`date +%M`
day=`date +%m/%d/%y`
let h=$H-1
echo DAY $DAY
echo H $H
echo M $M
echo day $day
echo h $h
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My result: (3 Replies)
Hello,
I try to insert a post because I've got a trouble to perform a unix job. But I didn't found which steps (procedure) I should follow. Could you help me?
I got a log by my Application box, like following:
gbosmam037:test >view Log_Server.csv
... (2 Replies)
Hi,
I have a input file with the following entries:
1one
2two
3three
1four
2five
3six
1seven
1eight
1nine
2ten
The output should be
1one
2two
3three
1four
2five
3six (2 Replies)
Hi,
I have a input file with the following entries:
1one
2two
3three
1four
2five
3six
1seven
1eight
1nine
2ten
2eleven
2twelve
1thirteen
2fourteen
The output should be: (5 Replies)
Hi friends, I want to convert 24 hour timing to 12 hour please help me...
my data file looks like this..
13-Nov-2011 13:27:36 15.32044 72.68502
13-Nov-2011 12:08:31 15.31291 72.69807
16-Nov-2011 01:16:54 15.30844 72.74028
15-Nov-2011 20:09:25 15.35096 ... (13 Replies)
Hi! all
can any one tell me how to compare current record of column with next and previous record in awk without using array
my case is like this
input.txt
0 32
1 26
2 27
3 34
4 26
5 25
6 24
9 23
0 32
1 28
2 15
3 26
4 24 (7 Replies)
I have data coming in the below format for each record
<?xml version="1.0" encoding="UTF-8" standalone="no"?><test_sox xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"><testdetials>....</test_sox>
<?xml version="1.0" encoding="UTF-8" standalone="no"?><test_sox... (8 Replies)
Hi,,
I have requirement that i need to get DISTINCT values from a table and if there are two records i need to update it to one record and then need to submit INSERT statements by using the updated value as a parameter. Here is the example follows..
SELECT DISTINCT ID FROM OFFER_GROUP WHERE... (1 Reply)
HI I am Trying to edit the below code to send email every day with difference of disk utilized in for last 24 hours but instead getting same usage everyday. can you please help me to point out where my calculation is going wrong. Thank you.
=================
#!/bin/bash
TODAY="at $(date... (0 Replies)
Discussion started by: Mi4304
0 Replies
LEARN ABOUT V7
at
AT(1) General Commands Manual AT(1)NAME
at - execute commands at a later time
SYNOPSIS
at time [ day ] [ file ]
DESCRIPTION
At squirrels away a copy of the named file (standard input default) to be used as input to sh(1) at a specified later time. A cd(1) com-
mand to the current directory is inserted at the beginning, followed by assignments to all environment variables. When the script is run,
it uses the user and group ID of the creator of the copy file.
The time is 1 to 4 digits, with an optional following `A', `P', `N' or `M' for AM, PM, noon or midnight. One and two digit numbers are
taken to be hours, three and four digits to be hours and minutes. If no letters follow the digits, a 24 hour clock time is understood.
The optional day is either (1) a month name followed by a day number, or (2) a day of the week; if the word `week' follows invocation is
moved seven days further off. Names of months and days may be recognizably truncated. Examples of legitimate commands are
at 8am jan 24
at 1530 fr week
At programs are executed by periodic execution of the command /usr/lib/atrun from cron(8). The granularity of at depends upon how often
atrun is executed.
Standard output or error output is lost unless redirected.
FILES
/usr/spool/at/yy.ddd.hhhh.uu
activity to be performed at hour hhhh of year day ddd of year yy. uu is a unique number.
/usr/spool/at/lasttimedone contains hhhh for last hour of activity.
/usr/spool/at/past directory of activities now in progress
/usr/lib/atrun program that executes activities that are due
pwd(1)SEE ALSO calendar(1), cron(8)DIAGNOSTICS
Complains about various syntax errors and times out of range.
BUGS
Due to the granularity of the execution of /usr/lib/atrun, there may be bugs in scheduling things almost exactly 24 hours into the future.
AT(1)