11-13-2005
searching by string length
Hi,
I want to search through a file that contains a whole dictionary of words, but I only want to retrieve the words that are 6 letters in length, and secondly, 6 characters in length or less.
How can I do this?
Right now I have this:
grep '^[a-z]' dictionary > results which grabs every word in the dictionary, regardless of length.
Thanks,
Jason
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LEARN ABOUT CENTOS
create_text_search_dictionary
CREATE TEXT SEARCH
DICTIONARY(7) PostgreSQL 9.2.7 Documentation CREATE TEXT SEARCH DICTIONARY(7)
NAME
CREATE_TEXT_SEARCH_DICTIONARY - define a new text search dictionary
SYNOPSIS
CREATE TEXT SEARCH DICTIONARY name (
TEMPLATE = template
[, option = value [, ... ]]
)
DESCRIPTION
CREATE TEXT SEARCH DICTIONARY creates a new text search dictionary. A text search dictionary specifies a way of recognizing interesting or
uninteresting words for searching. A dictionary depends on a text search template, which specifies the functions that actually perform the
work. Typically the dictionary provides some options that control the detailed behavior of the template's functions.
If a schema name is given then the text search dictionary is created in the specified schema. Otherwise it is created in the current
schema.
The user who defines a text search dictionary becomes its owner.
Refer to Chapter 12, Full Text Search, in the documentation for further information.
PARAMETERS
name
The name of the text search dictionary to be created. The name can be schema-qualified.
template
The name of the text search template that will define the basic behavior of this dictionary.
option
The name of a template-specific option to be set for this dictionary.
value
The value to use for a template-specific option. If the value is not a simple identifier or number, it must be quoted (but you can
always quote it, if you wish).
The options can appear in any order.
EXAMPLES
The following example command creates a Snowball-based dictionary with a nonstandard list of stop words.
CREATE TEXT SEARCH DICTIONARY my_russian (
template = snowball,
language = russian,
stopwords = myrussian
);
COMPATIBILITY
There is no CREATE TEXT SEARCH DICTIONARY statement in the SQL standard.
SEE ALSO
ALTER TEXT SEARCH DICTIONARY (ALTER_TEXT_SEARCH_DICTIONARY(7)), DROP TEXT SEARCH DICTIONARY (DROP_TEXT_SEARCH_DICTIONARY(7))
PostgreSQL 9.2.7 2014-02-17 CREATE TEXT SEARCH DICTIONARY(7)