08-25-2005
grep -A
i think it should do the deal if you want to collect the data for one hour of a specific day.
just do this :
grep -A 3 "08:23:2005 01:" data_file
where your file is data_file.
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LEARN ABOUT DEBIAN
getdate
GETDATE(1) User Commands GETDATE(1)
NAME
getdate - AME
SYNOPSIS
[-dv][-n dec][-f format] [ra dec sys] itype2otype [date and/or time]
DESCRIPTION
Convert date and time between various formats
[-dv][-n dec][-f format] itype2otype @file
itype: nfd=ISOFITS fd=FITS, dt=yyyy.mmdd, hr=hh:mm:ss, deg=dd:mm:ss
jd=Julian Date, mjd=Modified Julian Date hjd=Heliocentric Julian Date, mhjd=Modified HJD ep=epoch, epj=Julian epoch, epb=Besselian
epoch lt=local time, ut=UT, ts=seconds since 1950-01-01 now=current time, ang=fractional degrees
otype: fd=FITS, dt=yyyy.mmdd, jd=Julian Date, mjd=Modified Julian Date
hjd=Heliocentric Julian Date, mhjd=Modified HJD hr=hh:mm:ss, deg=dd:mm:ss, ang=fractional degrees ep=epoch, epj=Julian epoch,
epb=Besselian epoch ts=seconds since 1950-01-01, tsu=Unix sec, tsi=IRAF sec gst=Greenwich Sidereal Time, lst=Local Sidereal Time
@file: First one or two columns are in itype format ra dec sys: Need for Heliocentric conversions
-a: Append date to input file, if there is one
-d: Print date without time
-e: Print output as ET/TDT/TT converting from UT
-f: Format for output number (C printf)
-h hours: Longitude in hours, west positive
-l degrees: Longitude in degrees, west positive
-n: Number of decimal places in sec, epoch, JD
-t: Print time without date
-v: Verbose
getdate 3.8.4 June 2012 GETDATE(1)