can anyone see the awk syntax error near line 1? I keep getting this error and I'm not familiar with awk very well yet so it is hard for me to see the errors.
fyi: deleteuser* refers to files in the directory where each one ends with a different date
ls -1 /mfupload/prod02/ftp/deleteuser* |... (12 Replies)
Due to some syntax error, my below code is not working.
#!/usr/bin/ksh
nawk '
BEGIN {
cur_val=0; cur_zero=0; cur_nine=0;
sum_zero=0; sum_nine=0;
}
/^/ {
cur_val=substr($0,5,2);
if("cur_val" == "0")
{
... (3 Replies)
I generate a fullpath variable two different ways:
1) concat two variables rootpath and relpath to give me fullpath
2) use 'find' to get the fullpath
when I echo the variable, I get the same output for both. However,
I print the variable from method 1 in the below loop I get "awk syntax... (0 Replies)
hi there
i write one awk script file in shell programing
the code is related to dd/mm/yy to month, day year format
but i get an error
please can anybody help me out in this problem ??????
i give my code here including error
awk `
# date-month -- convert mm/dd/yy to month day,... (2 Replies)
Hi, I can't see what is wrong with the following command.
I am extracting a dollar amount (AMT_REJ, 6th field) from a comma delimited record and need to output it as numeric, removing the $sign and decimal point and output to another file. Everything seems to work except the $ sign which I need... (1 Reply)
Hi All,
I wrote a simple script.sh program
for i in seq (22)
do awk '$1==${i}' file1.txt|awk '{print $2}'> file${i}_study.txt
done
and then run it
%bash
%chmod +x script.sh
% ./script.sh
Give me error
awk: $1==${i}
awk: ^ syntax error
Do you have any idea why... (3 Replies)
Can anyone work out why this line has a syntax error?
awk '{if ($1==1) print NR,$0 } '${PROJECT}/${data_dir}/${ofolder}/STDEV/otimes_${per}_secs.dat > tmp2.txt
I've check that the file exists in the given location (1 Reply)
Could somebody gently point out the error of my ways in the below (the flu I'm fighting might be contributing to my current haplessness)
awk -F="\t" \
'{
for (i = 1; i <= NR; i++);
FNR == i;
{
if (length($3) < 56 && length($1) > 56)
$1=($1" "$2); $2=$3; $3=$4;
... (1 Reply)
I know the below code worked, but the syntax appears to be wrong and I can not seem to correct it. Thank you :).
awk 'FNR==NR {E; next }>$3 in E {print $3, $5}' medical_exome__genes.txt RefSeqGene.txt > update.txt
awk: cmd. line:1: FNR==NR {E; next }>$3 in E {print $3, $5}
awk: cmd.... (2 Replies)
Discussion started by: cmccabe
2 Replies
LEARN ABOUT DEBIAN
bbdb-areacode-split
BBDB-AREACODE-SPLIT.PL(1) General Commands Manual BBDB-AREACODE-SPLIT.PL(1)NAME
bbdb-areacode-split - Looks for phone numbers in your .bbdb
SYNOPSIS
bbdb-areacode-split <old-code> <new-code> <exchanges-file> [bbdb]
DESCRIPTION
Looks for phone numbers in your .bbdb with a particular area code and one of a set of exchanges and changes the area code. The old and new
area codes are specified on the command line, as is the location of a file that contains the exchanges that are being changed. (The format
of that file is very loose. Every three digit sequence will be used.)
This manual page was written for the Debian distribution because the original program does not have a manual page. Instead, it has docu-
mentation in the GNU Info format; see below.
SEE ALSO bbdb-cid(1), bbdb-unlazy-lock(1). bbdb-srv(1).
The bbdb is fully documented by The insidious Big Brother Database for mail and news, available via the Infonode bbdb
AUTHOR
This manual page was written by Joerg Jaspert (JJ) <joerg@goliathbbs.dnsalias.net>, for the Debian GNU/Linux system (but may be used by
others).
March 31, 2002 BBDB-AREACODE-SPLIT.PL(1)