Trying to write an if statement, which calls2 or 3 functions from within it.
code:
{if (($34 != "") && (NR != 1) && ($1 != "F"))
less_than(34, 0, "S1002a")
is_number(34,"S1002a")
}
But this is only treating the first function call, as part of the if.
and always executes is_number.... (1 Reply)
Hello,
I'm trying to use awk to print lines that match a regular expression.
I am using awk to print a record only if it contains N/A.
awk '/N/A/ {print $1}'
When executed the script returns "awk syntax error near line 1".
If I use /N//A/ it prints all records containing a "/", not... (2 Replies)
Hi ,
I have a simple question in awk, i have long string which i am getting for a grep command. the output contains 50 fields.
I need to display like first 5 fileds in a line and rest of all fields in the next line.
{ for(i=5;i<NF;++i) s= $i; print $1,$2,$3,$4,$5,"\n",$s}
Is the above... (1 Reply)
I have a file
CREATE TABLE DDD_EXT --- 1000
(
val u1
val u1
);
CREATE TABLE dsdasd_EXT --- 1323
(
val u1
val u1
);
CREATE TABLE AAAAAA_EXT --- 1222
(
val u1
val u1
);
CREATE TABLE E_EXT --- 11
(
val u1
val u1 (2 Replies)
Hi,
Probably a very weak question.. but I have tried all I know..
BPC0001:ANNUL_49542 0.0108 -0.0226 -0.0236 0.0042 0.0033 -0.0545 0.0376 0.0097 -0.0093 -0.032 Control
BPC0002:ANNUL_49606 0.0190 -0.0142 -0.0060 -0.0217 -0.0027 ... (3 Replies)
Hi,
let's assume i have an output below:
orgauser 23826 :E:Validity
senerse 2096
senerse 2111
senerse 21585
senerse 21596
root 12653 -bash
root 17262
root 17278
Some lines have not any string in their third column. I don't want to see those lines. i just want to see the lines... (3 Replies)
Can anyone tell me please what the "+" is doing in this awk command?
find / -user smith -type f -ls | awk '{ sum += $7 } END {print sum }'
Thanks,
George (2 Replies)
Hi All,
A very silly question:
How to just print the integer attached a particular string in a line by awk?
Ex:
Happy_world_foo123...So i just want the value 123 to be printed on the line where we have string "foo".
Thanks (16 Replies)
I have what a think is a simple question but I'm just a beginner in scripting. I'm my unix command line I run a date command that returns the following:
Wed Apr 3 10:39:30 EDT 2013
How do I awk out the "10" only in awk? Or is awk the way to do it or is there a better way? (7 Replies)
Here is an awk line I have in a bigger script that checks to see if nimsh process is running and does couple other things based on the output and runs on all servers.
ps -ef|grep -i nimsh|awk '{print $9}' and I am expecting output to be "/usr/sbin/nimsh"
I find that on some servers... (4 Replies)
Discussion started by: kvosu
4 Replies
LEARN ABOUT DEBIAN
igawk
IGAWK(1) Utility Commands IGAWK(1)NAME
igawk - gawk with include files
SYNOPSIS
igawk [ all gawk options ] -f program-file [ -- ] file ...
igawk [ all gawk options ] [ -- ] program-text file ...
DESCRIPTION
Igawk is a simple shell script that adds the ability to have ``include files'' to gawk(1).
AWK programs for igawk are the same as for gawk, except that, in addition, you may have lines like
@include getopt.awk
in your program to include the file getopt.awk from either the current directory or one of the other directories in the search path.
OPTIONS
See gawk(1) for a full description of the AWK language and the options that gawk supports.
EXAMPLES
cat << EOF > test.awk
@include getopt.awk
BEGIN {
while (getopt(ARGC, ARGV, "am:q") != -1)
...
}
EOF
igawk -f test.awk
SEE ALSO gawk(1)
Effective AWK Programming, Edition 1.0, published by the Free Software Foundation, 1995.
AUTHOR
Arnold Robbins (arnold@skeeve.com).
Free Software Foundation Nov 3 1999 IGAWK(1)