11-06-2002
That was a wrong claim... try this on command line...
echo +2345 | grep -E '^(\+|-)?[0-9]+$'
I hope you understood what '^(\+|-)?[0-9]+$' means...
Since you seem concerned with selective and intelligent matches, I would suggest you to go through some good book on regular expressions...
here is one worth it's bucks...
http://www.oreilly.com/catalog/regex2/
Cheers!
Vishnu.
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LEARN ABOUT DEBIAN
ns_parseurl
Ns_Url(3aolserver) AOLserver Library Procedures Ns_Url(3aolserver)
__________________________________________________________________________________________________________________________________________________
NAME
Ns_AbsoluteUrl, Ns_ParseUrl, Ns_RelativeUrl, Ns_SkipUrl - URL manipulation routines
SYNOPSIS
#include "ns.h"
int
Ns_AbsoluteUrl(Ns_DString *pds, char *url, char *baseurl)
int
Ns_ParseUrl(char *url, char **pprotocol, char **phost,
char **pport, char **ppath, char **ptail)
char *
Ns_RelativeUrl(char *url, char *location)
char *
Ns_SkipUrl(Ns_Request *request, int n)
_________________________________________________________________
DESCRIPTION
Ns_AbsoluteUrl(pds, url, baseurl)
Construct an URL based on baseurl but with as many parts of the incomplete url as possible. Return NS_OK or NS_ERROR.
Ns_ParseUrl(url, pprotocol, phost, pport, ppath, ptail)
Parse a URL into its component parts. Pointers to the protocol, host, port, path, and "tail" (last path element) will be set by ref-
erence in the passed-in pointers. The passed-in url will be modified.
Ns_RelativeUrl(url, location)
If the url passed in is for this server, then the initial part of the URL is stripped off. e.g., on a server whose location is
http://www.foo.com, Ns_RelativeUrl of "http://www.foo.com/hello" will return "/hello". Returns a pointer to the beginning of the
relative url in the passed-in url, or NULL if error. Will set errno on error.
Ns_SkipUrl(request, n)
Return a pointer n elements into the request's url.
SEE ALSO
nsd(1), info(n)
KEYWORDS
AOLserver 4.0 Ns_Url(3aolserver)