10-21-2002
It's quite simple really......you don't!!!
Linux doesn't require defragmentation like windows does. Read up on the different file systems to get a better understanding of why.
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LEARN ABOUT DEBIAN
read_allocate
read_allocate(3) Staden Package read_allocate(3)
NAME
read_allocate, read_deallocate - Allocate and deallocate the Read structure.
SYNOPSIS
#include <Read.h>
Read *read_allocate(
int num_points,
int num_bases);
void read_deallocate(
Read *read);
DESCRIPTION
These functions create and destroy Read structures. The Read structure is a generalised in-memory data structure used for holding trace
data information.
read_allocate() creates a Read structure large enough to hold num_points trace sample points and num_bases called bases. The allocated data
is then initialised to appropriate defaults, which are mainly zeros and null pointers.
read_deallocate() destroys a previously created Read structure. It is not sufficient to simply use the free() call instead.
RETURN VALUES
On successful completion, the read_allocate() function returns a pointer to a Read structure. Otherwise this function returns a null
pointer.
The read_deallocate() function returns no value.
SEE ALSO
read_reading(3), fread_reading(3), write_reading(3), fwrite_reading(3)
read_allocate(3)