Hi Chubler_XL, thanks for your answer. it works fine. since I am relatively new for unix/awk scripting. I am not able to fully understand the code. below is my understanding about this code, some part I don't know how it works and have some questions. could you please review and give me brief explanation
thanks in advance.
Code:
awk -v want="RECORD_COUNT,VALUE2,VALUE3" -F'[=\\][]' ' --- F'[=\\][]' need to understand how the regular exp works..
function prnsection(i) { --- function pass arg i in
if(length(section)) { --- if section is not empty do following
printf "%s",section; --- print section
for(i=1;i in keypos;i++) { --- for loop, max i is number of array keypos: keypos[value1]=1, keypos[value2]=2, keypos[values3]=3
printf " %s", keys[keypos[i]] --- array keys elements are: keys[1]=value1, keys[2]=value2, key[3]=value2
keys[keypos[i]]="MISSING" --- if array keys element doens't have value , assign value "missing"
}
printf "\n"
}
}
BEGIN {
for(i=split(want, keypos, ",");i;i--) { --- create array keypos element based on variable want
keys[keypos[i]]="MISSING"; --- create array keys if keys is empty then assign value missing.
}
}
NF>2 { prnsection(); section=$0 } ---if NF> 2 then call function and assign $0 to section. the function has one
--- argument, but here is empty,
---how the value be passed in?
---what's the purpose to call this function?
$1 in keys { keys[$1]=$0 }; --- first my understanding is $1 is VALUE1, VALUE2..., I tried command, with -F'[=\\][]'
----as delimiter, NF=1, not sure how it works.
END { prnsection() }' file ---here call the function to print result..
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