Sponsored Content
Top Forums UNIX for Beginners Questions & Answers Expand Variables and Wildcards into another variable. Post 303035139 by anbu23 on Wednesday 15th of May 2019 05:59:12 AM
Old 05-15-2019
Code:
file_path=${output_dir}
files_list=`ls ${output_dir}/*MIGRATE*${city_name}*.out`

This User Gave Thanks to anbu23 For This Post:
 

10 More Discussions You Might Find Interesting

1. UNIX for Dummies Questions & Answers

How can I put wildcards in an if statement that uses variables?

With the if statement: if How can I make it so it accepts a wildcard after the ${CURR_DAY_MONTH} variable? Putting a -f /webtrends/SUN/mrw2/access.${CURR_DAY_DAY}${CURR_DAY_MONTH}* won't work, right? I think I need some kind of special character so it knows the wildcard is... (3 Replies)
Discussion started by: LordJezo
3 Replies

2. Shell Programming and Scripting

how to seperate a variable in 2 variables

Dear all, i dont know how to split one variable value in 2 variable. please send me any example. variable1= "abcde developer" now i want to seperate the values and seperator is space. (6 Replies)
Discussion started by: intikhabalam
6 Replies

3. UNIX for Dummies Questions & Answers

how to expand environment variables in a file?

I am new to unix and would appreciate if someone could help. I have an environment variable SourceFilePath=/db1/Src/test set on the unix server. I want to expand this SHELL variable in a file using any command sed, awk etc File contents is as follows: var=$SourceFilePath/file.txt ... (2 Replies)
Discussion started by: debbie15
2 Replies

4. UNIX for Dummies Questions & Answers

Using wildcards in variables in zsh

Probably a stupid question... how do I use a wildcard in a variable in zsh? If I do: var=* echo $var in bash, it will print all files/directories in the current directory. If I do it in zsh, it will only output an asterisk without the wildcard functionality. Thanks in advance! (1 Reply)
Discussion started by: RainbowLAr
1 Replies

5. Shell Programming and Scripting

For loop using input file doesn't expand variables

Hi, I'm using a for loop reading from an input file that contains files, whose path includes a variable name. But the for loop doesn't expand the variable and therefore can't find the file. Here's an example: File BACKUPFILES /home/John/alpha /home/Sue/beta... (8 Replies)
Discussion started by: Hesiod
8 Replies

6. Shell Programming and Scripting

Expand an environment variable in sed, when the variable contains a slash

I'm trying to make a sed substitution where the substitution pattern is an environment variable to be expanded, but the variable contains a "slash". sed -e 's/<HOME_DIRECTORY>/'$HOME'/'This gives me the following error: sed: -e expression #1, char 21: unknown option to `s'Obviously this is... (2 Replies)
Discussion started by: Ilja
2 Replies

7. Shell Programming and Scripting

dynamic variables - eval - expand etc.

Hello, so i'm making a script, using dynamic variables and trying to expand them. So far it hasn't worked out too well so it seems that I need some help from you, the elite. Example: #!/bin/sh counter=0 until (($counter>5)) counter2=1 until (($counter2>6)); do if ;... (5 Replies)
Discussion started by: TehOne
5 Replies

8. Shell Programming and Scripting

How to set a variable name from another variables value?

Experts, I want to set value of variables like this in bash shell: i=5 ; L=100 I want variable d5 (that is d(i) ) to be assign the value of $L , d$i=$L ; echo $d5 Not working Thanks., (3 Replies)
Discussion started by: rveri
3 Replies

9. Shell Programming and Scripting

Variable variables

Hello, Can you please help here? DAY=$1 MONTH_MONDAY_YEAR = 1 2 3 4 for i in ${MONTH_${DAY}_YEAR} do echo ${i} done ./test.sh MONDAY ./test.sh: line 3: MONTH_MONDAY_YEAR: command not found ./test.sh: line 10: ${MONTH_${DAY}_YEAR}: bad substitution (6 Replies)
Discussion started by: vino_hymi
6 Replies

10. Shell Programming and Scripting

How to handle grepping variable data containing wildcards?

I have a lot of files with keywords and unique names. I'm using a shell script to refer to a simple pattern file with comma separated values in order to match on certain keywords. The problem is that I don't understand how to handle the wildcard values when I want to skip over the unique names. ... (5 Replies)
Discussion started by: abercrom
5 Replies
envdir(8)						      System Manager's Manual							 envdir(8)

NAME
envdir - runs another program with environment modified according to files in a specified directory. SYNOPSIS
envdir d child DESCRIPTION
d is a single argument. child consists of one or more arguments. envdir sets various environment variables as specified by files in the directory named d. It then runs child. If d contains a file named s whose first line is t, envdir removes an environment variable named s if one exists, and then adds an environ- ment variable named s with value t. The name s must not contain =. Spaces and tabs at the end of t are removed. Nulls in t are changed to newlines in the environment variable. If the file s is completely empty (0 bytes long), envdir removes an environment variable named s if one exists, without adding a new vari- able. EXIT CODES
envdir exits 111 if it has trouble reading d, if it runs out of memory for environment variables, or if it cannot run child. Otherwise its exit code is the same as that of child. SEE ALSO
supervise(8), svc(8), svok(8), svstat(8), svscanboot(8), svscan(8), readproctitle(8), fghack(8), pgrphack(8), multilog(8), tai64n(8), tai64nlocal(8), setuidgid(8), envuidgid(8), softlimit(8), setlock(8) http://cr.yp.to/daemontools.html envdir(8)
All times are GMT -4. The time now is 04:10 PM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy