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Full Discussion: Ps ax with grep in loop
Top Forums Shell Programming and Scripting Ps ax with grep in loop Post 303019936 by nms on Tuesday 10th of July 2018 11:33:11 AM
Old 07-10-2018
Ps ax with grep in loop
Hello,

I have built the following script to check if processes supplied by the argument are running or not.

Code:
#!/bin/bash

PROCLIST=$1

PROCESS="0"
ERROR_PROCS=""
IFS='+'
read -ra ADDR <<< "$PROCLIST"
for PROC in "${ADDR[@]}"; do
                if [ `ps ax | grep $PROC | grep -v grep | wc -l` -lt 1 ]; then
                PROCESS=1
                ERROR_PROCS="$ERROR_PROCS""$PROC ";
                fi
        done

        if [ $PROCESS -eq 1 ]; then
                echo "CRITICAL - One or more processes ($ERROR_PROCS) not running"
                exit 2
        fi


echo "OK - All monitored processes are running. Process: $PROCLIST"
exit 0

it seems it works fine apart from the fact the "ps ax | grep "process" | wc -l" gives a higher count than expected.
For example, if we take the process named "test" (which doesn't exist), it returns a count of 2.

Code:
[root@matt Linux]# ps ax | grep test | grep -v grep
[root@matt Linux]#

if We run the script with verbose:

Code:
[root@matt Linux]# bash -x ./test2.sh test
+ PROCLIST=test
+ PROCESS=0
+ ERROR_PROCS=
+ IFS=+
+ read -ra ADDR
+ for PROC in '"${ADDR[@]}"'
++ ps ax
++ grep test
++ wc -l
++ grep -v grep
+ '[' 2 -lt 1 ']'
+ '[' 0 -eq 1 ']'
+ echo 'OK - All monitored processes are running. Process: test'
OK - All monitored processes are running. Process: test
+ exit 0

What could be the reason that it captures the value of 2? This also happens if the process does exist. in that case, it returns a 3.

Rgds,

Matthew
 

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NAME

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SYNOPSIS

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