Help on grep in a do while loop

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# 1  
Old 06-24-2011
Help on grep in a do while loop

So this is what I'm trying to do:

I have a file called registry.txt which has a list of registry entries I want to search for.

I have another file called inctrl.txt on which I want to perform the search on.

Here's the example contents of registry.txt
SOFTWARE\Microsoft\Security Center

Here's the example contents of inctrl.txt
HKEY_LOCAL_MACHINE\SOFTWARE\Microsoft\Security Center\AntiVirusDisableNotify!=dword:0

Here's the script which is supposed to do the searching.


exec < ${REG}
while read LINE
    egrep -i ${LINE} ${IN}

The desired output should be:

HKEY_LOCAL_MACHINE\SOFTWARE\Microsoft\Security Center\AntiVirusDisableNotify!=dword:0

But I'm not able to get the job done. I think it has to do with escaping the characters before grepping, but I just can't figure out the right combination.

Can someone please help me?

Thanks in advance
# 2  
Old 06-24-2011
No need for a loop or for re-reading inctrl.txt over and over and over again. Just tell grep to read the text to match from registry.txt with the -f switch. And since you aren't using regular expressions, it's safest to specify fixed string matching with -F.

grep -Ff registry.txt inctrl.txt

This User Gave Thanks to alister For This Post:
# 3  
Old 06-24-2011
Beautiful. There's always something new to learn. Thanks a ton Alister

---------- Post updated at 11:32 PM ---------- Previous update was at 11:27 PM ----------

Just out of curiosity....How do you get it right in the do while loop ?
# 4  
Old 06-24-2011
Originally Posted by r4v3n
Just out of curiosity....How do you get it right in the do while loop ?
-F, as mentioned. That tells it to interpret the pattern as a string instead of a regex. But the 'right' way would be to use the features of the program.

Last edited by Corona688; 06-24-2011 at 03:26 PM..
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