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Top Forums Programming Segmentation fault when I pass a char pointer to a function in C. Post 303016280 by Corona688 on Monday 23rd of April 2018 06:09:15 PM
Old 04-23-2018
Quote:
Originally Posted by dryden
Yes, interesting. So because that array stores actual memory on the stack, you cannot change what it points to, hmmmm. I thought arrays were pointers, until I tried to assign an array (pointer) to something else ;-). [I mean the reverse, assign something else to that array].
It's implicitly a pointer, implemented as one internally, but the same way you're not allowed to change a string's contents, you're not allowed to change its value. Hardcoded.
 

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ARRAY_POP(3)								 1							      ARRAY_POP(3)

array_pop - Pop the element off the end of array

SYNOPSIS
mixed array_pop (array &$array) DESCRIPTION
array_pop(3) pops and returns the last value of the $array, shortening the $array by one element. Note This function will reset(3) the array pointer of the input array after use. PARAMETERS
o $array - The array to get the value from. RETURN VALUES
Returns the last value of $array. If $array is empty (or is not an array), NULL will be returned. ERRORS
/EXCEPTIONS This function will produce an error of level E_WARNING when called on a non-array. EXAMPLES
Example #1 array_pop(3) example <?php $stack = array("orange", "banana", "apple", "raspberry"); $fruit = array_pop($stack); print_r($stack); ?> After this, $stack will have only 3 elements: Array ( [0] => orange [1] => banana [2] => apple ) and raspberry will be assigned to $fruit. SEE ALSO
array_push(3), array_shift(3), array_unshift(3). PHP Documentation Group ARRAY_POP(3)
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