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Top Forums Shell Programming and Scripting Using shell to generate case statement Post 303000289 by RudiC on Saturday 8th of July 2017 07:58:18 AM
Old 07-08-2017
Not clear.

Is the requirement "For every rule in table 1 scour table 2 for one (or more?) matching records and print out one case in the case statement"? Match means identical yes / no (value / empty) patterns between the two tables. As line 2 and 4 in table 2 have the same yes / no pattern, you want two cases printed?

The third case statement cannot be produced with any of the keys in table 1.
Why do you need table 1 at all? The case statement shown can be produced from table 2 alone.
Is it correct that keys 2,3, and 4 are not applicable to table 2 shown as P_CODE is not empty in any record?
Why, in the second case, is M_SRC = 5 and not 6 as in table 2?
Do you really mean "D means this column used for the rule", or the opposite?
 

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DB2_FIELD_TYPE(3)							 1							 DB2_FIELD_TYPE(3)

db2_field_type - Returns the data type of the indicated column in a result set

SYNOPSIS
string db2_field_type (resource $stmt, mixed $column) DESCRIPTION
Returns the data type of the indicated column in a result set. PARAMETERS
o $stmt - Specifies a statement resource containing a result set. o $column - Specifies the column in the result set. This can either be an integer representing the 0-indexed position of the column, or a string containing the name of the column. RETURN VALUES
Returns a string containing the defined data type of the specified column. If the specified column does not exist in the result set, db2_field_type(3) returns FALSE. SEE ALSO
db2_field_display_size(3), db2_field_name(3), db2_field_num(3), db2_field_precision(3), db2_field_scale(3), db2_field_width(3). PHP Documentation Group DB2_FIELD_TYPE(3)
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