But I want to copy files with a certain date over from one dir to another.
How do i do this?
I tried using the for loop like this :
As you can see, it does the loop for times, (i.e copying 2 files 4 times).
This is not I want. What I want is for the script to recognize the files dated from the 16th to the latest date, and copy it over to the other directory, without repeating or overwriting like above.
Hello
I am executing the following script
nawk 'NR == 1 || substr($0,63,5) ~ /H... / && \
_++ == 2 { fn && close(fn); fn = "part_" ++c; _ = 1 }
{ print > fn }' sample.dat
When i execute as it is it is executing fine. but when i execute the whole script as a single line like below
... (2 Replies)
I am executing the below in telnet
#!/usr/bin/ksh
File1=simple.txt # The file to check
LogFile=simple.log # The log file
DelayMax=30 # Timeout delay
Tolerance=2
# BEGIN ##############################
while true
do
StampNow=$(date +%s)/60 # stamp in minutes
... (3 Replies)
Hi ,
I m getting an error after executing the script.
My script.
Script is used to find out the date on 8 different machines(mentioned in SERVERNAMES file).
I have added public key to avoid ssh password and ssh without password working fine.
#!/bin/sh
fn_VMFind()
{
Date=`ssh -t... (5 Replies)
Hi
Please assist. Im getting an error while execuing the script name d "cdsnd.basel.cd_new
" as siiadm user. Thanks.
siiadm> ls -l
total 64
-rwxr-xr-x 1 siiadm sboadm 1004 Sep 17 2008 cdsnd.basel.cd
-rwxr-xr-x 1 siiadm sapsys 998 Nov 16 09:14 cdsnd.basel.cd_new... (1 Reply)
Hi,
I am not able to figure out what the problem is:
getting the following error
sqltst.sh: 1: not found
here is the script
#!/bin/sh
. /home/dev1/.profile
. /home/dev1/.infenv
`sqlplus -s $REPDB_LOGON << EOF
SET SERVEROUT ON
SET FEEDBACK OFF
SET HEADING OFF
SET TRIMSPOOL... (4 Replies)
hi all,
i am getting libssh2 error while executing script in RHEL 6, when i locate that file its not there below is the ouput of this
# locate libssh2_agent_init
# cat /etc/issue
Red Hat Enterprise Linux Server release 6.1 (Santiago)
Kernel \r on an \m
how do i resolve this issue, i... (1 Reply)
I have the following script test.sh owned by dwdev account and group dwdev, the permissions on the script are as follows.
-rw-r-x--- 1 dwdev dwdev 279 Sep 17 13:19 test.sh
Groups:
cat /etc/group | grep dwdev
dwdev:x:704:dwdev
dwgroup:x:725:dwdev
writers:x:726:dwdev
User:
cat /etc/passwd |... (3 Replies)
getting error as below while executing script in linux.
OS version:
Linux VGP-3GPSDB-LX 3.10.0-514.el7.x86_64 #1 SMP Wed Oct 19 11:24:13 EDT 2016 x86_64 x86_64 x86_64 GNU/Linux
./imxtract.sh: line 395: unexpected EOF while looking for matching ``'
./imxtract.sh: line 402: syntax error:... (1 Reply)
Discussion started by: Riverstone
1 Replies
LEARN ABOUT PHP
intlcalendar.getminimaldaysinfirstweek
INTLCALENDAR.GETMINIMALDAYSINFIRSTWEEK(3) 1 INTLCALENDAR.GETMINIMALDAYSINFIRSTWEEK(3)IntlCalendar::getMinimalDaysInFirstWeek - Get minimal number of days the first week in a year or month can have
Object oriented style
SYNOPSIS
public int IntlCalendar::getMinimalDaysInFirstWeek (void )
DESCRIPTION
Procedural style
int intlcal_get_minimal_days_in_first_week (IntlCalendar $cal)
Returns the smallest number of days the first week of a year or month must have in the new year or month. For instance, in the Gregorian
calendar, if this value is 1, then the first week of the year will necessarily include January 1st, while if this value is 7, then the week
with January 1st will be the first week of the year only if the day of the week for January 1st matches the day of the week returned by
IntlCalendar.getFirstDayOfWeek(3); otherwise it will be the previous years last week.
PARAMETERS
o $cal
- The IntlCalendar resource.
RETURN VALUES
An int representing a number of days or FALSE on failure.
EXAMPLES
Example #1
IntlCalendar.getMinimalDaysInFirstWeek(3)
<?php
ini_set('date.timezone', 'UTC');
ini_set('intl.default_locale', 'en_US');
$cal = new IntlGregorianCalendar(2013, 0 /* January */, 2);
var_dump(IntlDateFormatter::formatObject($cal, 'cccc')); // Wednesday
var_dump($cal->getMinimalDaysInFirstWeek(), // 1
$cal->getFirstDayofWeek()); // 1 (Sunday)
// Week 1 of 2013
var_dump(IntlDateFormatter::formatObject($cal, "'Week 'w' of 'Y"));
$cal->setMinimalDaysInFirstWeek(4);
// Still Week 1 of 2013 (1st week has 5 days in the new year)
var_dump(IntlDateFormatter::formatObject($cal, "'Week 'w' of 'Y"));
$cal->setMinimalDaysInFirstWeek(6);
// Week 53 of 2012
var_dump(IntlDateFormatter::formatObject($cal, "'Week 'w' of 'Y"));
The above example will output:
string(9) "Wednesday"
int(1)int(1)string(14) "Week 1 of 2013"
string(14) "Week 1 of 2013"
string(15) "Week 53 of 2012"
PHP Documentation Group INTLCALENDAR.GETMINIMALDAYSINFIRSTWEEK(3)