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Top Forums Shell Programming and Scripting Splitting multiple fields of /usr/bin/id Post 302994996 by RudiC on Thursday 30th of March 2017 10:12:45 AM
Old 03-30-2017
  1. /.../ is a regular expression; c.f. man awk: "Regular expressions are enclosed in slashes". A single / is pointless.
    ^ anchors the regex at begin-of-line (or string).
    .* represents "any char, zero or more times".
    = terminates this special regex. As we are sure there's only ONE = in $1, no additional measures need to be taken.
    | is the alternation operator ("or"), so multiple regexes can be matched
  2. Yes, that's why I used two function calls: for different results. If you accept leading and trailing spaces, try gsub (/^.*=|\)|\(/, " ", $1) and drop the sub.
  3. Semicolons separate commands in awk, as do line feeds. gsub modifies $1, then sub works on that mod'd $1
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groups(1)							   User Commands							 groups(1)

NAME
groups - print group membership of user SYNOPSIS
groups [user]... DESCRIPTION
The command groups prints on standard output the groups to which you or the optionally specified user belong. Each user belongs to a group specified in /etc/passwd and possibly to other groups as specified in /etc/group. Note that /etc/passwd specifies the numerical ID (gid) of the group. The groups command converts gid to the group name in the output. EXAMPLES
The output takes the following form: example% groups tester01 tester02 tester01 : staff tester02 : staff example% FILES
/etc/passwd /etc/group ATTRIBUTES
See attributes(5) for descriptions of the following attributes: +-----------------------------+-----------------------------+ | ATTRIBUTE TYPE | ATTRIBUTE VALUE | +-----------------------------+-----------------------------+ |Availability |SUNWcsu | +-----------------------------+-----------------------------+ SEE ALSO
group(4), passwd(4), attributes(5) SunOS 5.11 14 Sep 1992 groups(1)
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